Answer:
Think of it like a number line. If you start at 2 and move three to the left you land on -1.
You have to estimate the slope of the tangent line to the graph at <em>t</em> = 10 s. To do that, you can use points on the graph very close to <em>t</em> = 10 s, essentially applying the mean value theorem.
The MVT says that for some time <em>t</em> between two fixed instances <em>a</em> and <em>b</em>, one can guarantee that the slope of the secant line through (<em>a</em>, <em>v(a)</em> ) and (<em>b</em>, <em>v(b)</em> ) is equal to the slope of the tangent line through <em>t</em>. In this case, this would be saying that the <em>instantaneous</em> acceleration at <em>t</em> = 10 s is approximately equal to the <em>average</em> acceleration over some interval surrounding <em>t</em> = 10 s. The smaller the interval, the better the approximation.
For instance, the plot suggests that the velocity at <em>t</em> = 9 s is nearly 45 m/s, while the velocity at <em>t</em> = 11 s is nearly 47 m/s. Then the average acceleration over this interval is
(47 m/s - 45 m/s) / (11 s - 9 s) = (2 m/s) / (2 s) = 1 m/s²
Answer:
The answer is 317/5
Step-by-step explanation:
Answer:
Idk the answer but if we run out of comments we use these
Step-by-step explanation:
Answer:
(f•g)(x) = 3x^2 -1/3
Step-by-step explanation:
The solid dot in (f•g)(x) is assumed to mean you want the product of the functions, not their composition. So, ...
(f•g)(x) = f(x)•g(x) = (x -1/3)(3x +1) = x(3x +1) -1/3(3x +1) = 3x^2 +x -x -1/3
(f•g)(x) = 3x^2 -1/3
