The derivative, f'(x) = 6x^2+1, is never negative, so f(x) is monotonic, hence invertible.
f'(-2) = 6(-2)²+1 = 25
If point (-2, -26) is on the graph of function f(x), and the slope is 25 there, then (-26, -2) is on the graph of f⁻¹(x), and the slope is 1/25 there. The equation of the tangent line throught that point can be written in point-slope form as
... y +2 = (1/25)(x +26)
Answer:
Step-by-step explanation:
Answer:
10m.
Step-by-step explanation:
Since there is no remainder we simply need to find the least common multiple of each of the lengths of Janice and Jasmin's strings until we find a multiple that matches for each. Like so...
2*1 = 2 5*1 = 5
2*2 = 4 5*2 = 10
2*3 = 6
2*4 = 8
2*5 = 10
Finally, we have found the first common multiple which is 10m. That means that the shortest equal length for both Janice's and Jasmin's ribbon is 10m.
By definition, the formula for finding the area of a trapezoid is
A = [(b1 + b2) x h] / 2
Where,
b1: Base 1
b2: Base 2
h: height, or distance between bases.
Substituting we have:
A = ((5 + 4) * (2.5)) / 2
A = 11.25 feet ^ 2
Answer:
the area of the seat is:
A = 11.25 feet ^ 2