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Scrat [10]
2 years ago
5

If I only want to make 500 mL of a 1.25% bleach solution, how many milliliters of bleach would I need? Show your work or explain

how to figure it out.
Chemistry
1 answer:
kiruha [24]2 years ago
4 0

Answer:

  6.25 mL

Explanation:

1.25% of 500 mL is ...

  0.0125×(500 mL) = 6.25 mL

Since 1.25% of the 500 mL of solution is bleach, that's how much you need. That amount is 6.25 mL.

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Looking at the following equation, what coefficient should be placed in front of the H2? Fe + H2SO4 --> Fe2(SO4)3 + H2
Hatshy [7]

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3 (three)

Explanation:

2 Fe + 3H2SO4 = Fe2(SO4)3 + 3 H2 (basically just balance both sides)

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Who has the most sensitive taste buds?<br><br> the elderly<br> adults<br> babies<br> teenagers
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The melting point of the alkali metals (increased/decreases) from lithium to francium
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How many atoms are in one molecule of Iron II sulfate
dezoksy [38]
Answer:
             The number of atoms contained by one molecule of Iron (II) Sulfate are 6.

Explanation:
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5 0
3 years ago
In 1983, a pilot miscalculated the fuel requirement for Air Canada Fight 143 from Montreal to Edmonton. Halfway through the flig
drek231 [11]

Answer:

27,397.23 L would be needed for a successful trip.

Explanation:

The problem gives us <u>the density (ρ) of the fuel,</u> by telling us that there are 803 g of fuel in 1 L, in which case:

ρ=\frac{mass}{Volume}=\frac{803g}{1L}  =803\frac{g}{L}

The required mass of fuel is 2.2 * 10⁴ kg, we can convert this value into g:

2.2 * 10⁴ kg * \frac{1000g}{1kg} = 2.2 * 10⁷ g

We calculate the required volume (V), using the mass and density:

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Thus 27,397.23 L would be needed for a successful trip.

5 0
3 years ago
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