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2 years ago

5

If I only want to make 500 mL of a 1.25% bleach solution, how many milliliters of bleach would I need? Show your work or explain

how to figure it out.

1 answer:

kiruha [24]2 years ago

4 0

Answer:

6.25 mL

Explanation:

1.25% of 500 mL is ...

0.0125×(500 mL) = 6.25 mL

Since 1.25% of the 500 mL of solution is bleach, that's how much you need. That amount is 6.25 mL.

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The number of positive changes in the nucleus of an atom is equal to

raketka [301]

Answer:

The number of positive charges in nucleus of an atoms are equal to the atomic number and also positive charges are equal to the negative charges which are electrons in neutral atom.

Explanation:

An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

Electron:

The electron is subatomic particle that revolve around outside the nucleus and has negligible mass. It has a negative charge.

Symbol= e⁻

Mass= 9.10938356×10⁻³¹ Kg

It was discovered by j. j. Thomson in 1897 during the study of cathode ray properties.

Neutron and proton:

Neutron and proton are present inside the nucleus. Proton has positive charge while neutron is electrically neutral. Proton is discovered by Rutherford while neutron is discovered by James Chadwick in 1932.

Symbol of proton= P⁺

Symbol of neutron= n⁰

Mass of proton=1.672623×10⁻²⁷ Kg

Mass of neutron=1.674929×10⁻²⁷ Kg

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.

For example

The carbon have six protons and six neutrons so its atomic mass is 12 amu and atomic number is six.

8 0

2 years ago

The reaction shown below has a positive enthalpy change and a negative entropy change. 2C (s) + 2H2 (g) yields C2H4 (g) Which of

Drupady [299]

Answer is: <span>The reaction will not be spontaneous at any temperature.

</span>

<span>Gibbs free energy (G) determines if reaction will proceed spontaneously.
ΔG = ΔH - T·ΔS.
ΔG - changes in Gibbs free energy.
ΔH - changes in enthalpy.
ΔS - changes in entropy.
T is temperature in Kelvins.
When ΔS < 0 (negative entropy change) and ΔH > 0 (endothermic reaction), the process is never spontaneous (ΔG> 0).</span>

5 0

2 years ago

What is the molar solubility of agcl in 0. 30 m nacl at 25°C. ksp for agcl is 1. 77 × 10^-10.

Rzqust [24]

Molar solubility of AgCl will be 0.59 × $10^{-10}$ M.

The amount of a chemical that can dissolve in one liter of a solution before reaching saturation is known as its molar solubility. This implies that the quantity of a substance it can disintegrate in a solution even before the solution becomes saturated with that particular substance is determined by its molar solubility.

A compound's molar solubility would be the measure of how many moles of such a compound must dissolve to produce one liter of saturated solution. The molar solubility unit will be mol L-1.

Calculation of molar solubility:

Given data:

M = 0.30 M

$K_{sp}$ = 1.77 × $10^{-10}$

The reaction can be written as:

AgCl ⇔ $Ag^{+} + Cl^{-}$

s s (s+0.30)

$K_{sp}$ = [ $Ag^{+}$ ]+ [ $Cl^{-}$ ]

1.77 × $10^{-10}$ = s (0.30)

s = 1.77 × $10^{-10}$ / 0.3

s = 0.59 × $10^{-10}$ M

Therefore, molar solubility of AgCl will be 0.59 × $10^{-10}$ M.

To know more about molar solubility

brainly.com/question/16243859

#SPJ4

3 0

1 year ago

Determine the molar mass of barium sulfide, BaS

matrenka [14]

Answer: 169.39 g/mol

Explanation:

3 0

3 years ago

If the mass of the baking soda before the reaction was 10 grams and the mass of the vinegar was 15 grams and all of the baking s

Masteriza [31]

Answer:

8.946g NaHCO₃,

14.475g H₂O,

1.025g CH₃COO⁻Na⁺,

0.500g CO₂.

Explanation:

Baking soda (NaHCO₃) reacts with vinegar (CH₃COOH 5%) producing CH₃COO⁻Na⁺, H₂O and CO₂, thus:

NaHCO₃ + CH₃COOH → CH₃COO⁻Na⁺ + H₂O + CO₂

10g of NaHCO₃ are:

10g × (1mol / 84g) = 0.119 moles NaHCO₃

Moles of CH₃COOH in 15g of vinegar are:

15g vinegar × 5% = 0.75g CH₃COOH × (1mol / 60g) = 0.0125moles CH₃ COOH

After reaction, moles of NaHCO₃ that remains are:

0.119mol - 0.0125mol = <em>0.1065 moles NaHCO₃</em>

In mass:

0.1065mol ₓ (84g / 1mol) = <em>8.946g NaHCO₃</em>

Acetic acid reacts completely producing 0.0125moles of CH₃COO⁻Na⁺, water and CO₂. In mass:

CH₃COO⁻Na⁺ = 0.0125mol ₓ (82.03g / 1mol) = <em>1.025g CH₃COO⁻Na⁺</em>

H₂O = 0.0125mol ₓ (18.01g / 1mol) = <em>0.225g H₂O</em>

CO₂ = 0.0125mol ₓ (40g / 1mol) = <em>0.500g CO₂</em>

Now, 95% of vinegar is water (Doesn't react), that is:

15g × 95% = 14.25g H₂O. Total mass of water is:

14.25g + 0.225g = <em>14.475g H₂O</em>

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Total mass is:

8.946g + 14.475g H₂O + 1.025g + 0.500g ≈ 25g. The same than initial mass following law of conservation of matter.

6 0

3 years ago