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FromTheMoon [43]
3 years ago
12

Identify a false statement about how to protect iron from corrosion.

Chemistry
2 answers:
saw5 [17]3 years ago
6 0
Wouldn’t it be “B”? Can’t soemthing still get corroded under paint?
malfutka [58]3 years ago
5 0

Attach a metal that is more easily reduced i took the test

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What change would increase the amount of solid solute able to be dissolved in liquid water?
exis [7]
Bonjour,

increasing temperature.
for many solids dissolved in liquid water, the solubility increases with temperature.
3 0
2 years ago
What are the Sun's layers, beginning with the innermost and moving out.
Lemur [1.5K]
Core, radiative zone, convective zone, photosphere, chromosphere, corona 
4 0
3 years ago
What is the best definition of weight​
LenKa [72]

Answer:

a body's relative mass or the quantity of matter contained by it, giving rise to a downward force; the heaviness of a person or thing.

really depending on what weight you are referring to but thats the number 1 on dictonary

7 0
1 year ago
Read 2 more answers
Now you will solve the same problem as above, but using the quadratic formula instead of iterations, to show that the same value
Dafna1 [17]

Answer:

a: 1

b: 4.5x10⁻⁴

c: 1.125x10⁻⁶

[H₃O⁺] = 0.000859M

Explanation:

As HNO₂ is a weak acid, its equilibrium in water is:

HNO₂(aq) + H₂O(l) ⇄ H₃O⁺(aq) + NO₂⁻(aq)

Equilibrium constant, ka, is defined as:

ka = 4.5x10⁻⁴ = [H₃O⁺] [NO₂⁻] / [HNO₂] <em>(1)</em>

Equilibrium concentration of each specie are:

[HNO₂] = 0.00250M - x

[H₃O⁺] = x

[NO₂⁻] = x

Replacing in (1):

4.5x10⁻⁴ = x × x / 0.00250M - x

1.125x10⁻⁶ - 4.5x10⁻⁴x = x²

0 = x² + 4.5x10⁻⁴x - 1.125x10⁻⁶

As the quadratic equation is ax² + bx + c = 0

Coefficients are:

a: 1

b: 4.5x10⁻⁴

c: 1.125x10⁻⁶

Now, solving quadratic equation:

x = -0.0013 → False answer, there is no negative concentrations.

<em>x = 0.000859</em>

As [H₃O⁺] = x; <em>[H₃O⁺] = 0.000859M</em>

I hope it helps!

6 0
2 years ago
Butane, C4H10, is the gas burned in disposable lighters. How many moles of oxygen are needed to burn 5.0 mol of butane in a ligh
Olegator [25]

Answer:

32 mol

Explanation:

Step 1: Write the balanced equation.

C₄H₁₀ + 6.5 O₂ → 4 CO₂ + 5 H₂O

Step 2: Establish the appropriate molar ratio.

The molar ratio of C₄H₁₀ to O₂ is 1:6.5

Step 3: Calculate the moles of oxygen needed to burn 5.0 mol of butane.

We use the molar ratio established in the previous step.

5.0molC_4H_{10} \times \frac{6.5molO_2}{1molC_4H_{10} } = 32molO_2

4 0
3 years ago
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