Write 90% as a fraction or mixed number in simplest form
2 answers:
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Answer:
So in range "-35.6108 to 39.73"; 50% data set can be found
ux = 37.6704 unites
Step-by-step explanation:
Step One: State the given parameters
From the question we are given that
mean Ц =2.06 unites
Standard deviation б is = 55.85 unites
Probability density → Normal
Let assume that it is symmetrically distributed about the mean
Step Two: Determine the range of the values
Our goal is to determine the range of values in which 50% of the data set should be found . Assuming that the range is from to
and between these these we found 50% data set Hence from 0 up to
we found 25% and up to
we found 75% of the data set therefore z value corresponding to
is - 0.6745 and the the z value corresponding to
is +0.6745 (Refer to the z-table for normal distribution) as shown o the diagram on the first uploaded image
The formula for z is
z =
for ,z = - 0.6745 ,substituting into the formula
=> -37.67 = -2.06
=> = -35.6108 unites
for , z = 0.6745 , substituting into the formula
=> 37.67 = -2.06
=> = 39.73 units
So in range "-35.6108 to 39.73"; 50% data set can be found
ux = (39.73 - (-35.73) )/2
= 37.6704 unites
