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cupoosta [38]
3 years ago
6

I was born 14 yrs ago, my sister was born 18 yrs ago, my step sister was born 21 yrs ago, my mom was born 43 years ago. Wha is t

he range between my age and my step sisters' age?
Mathematics
1 answer:
LiRa [457]3 years ago
7 0

Between "my" age and "my" step sisters' age there is 7 years, the range is 7 years

Hope this helps

-GoldenWolfX

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-35 = 7t, solve for t?
Debora [2.8K]
If you divide by 7 on both sides to get rid of t, you get -5!
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The zoo feeds the tortoise, rhinoceros, and zebra a total of 23 pounds of vegetables a day. How many pounds does the zoo feed th
vekshin1

If I understand your question correctly, you want to know how many pounds of vegetables the zoo feeds the animals a month if its a 30 day month?

In that case it would be 23 pounds times 30 days which is 690 pounds of vegetables. SO the zoo feeds the animals 690 pounds of vegetables to the animals each month.

Is that what your asking for?

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where is the question?

Step-by-step explanation:

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3 years ago
Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x
BaLLatris [955]

Answer:

The area of the region is 25,351 units^2.

Step-by-step explanation:

The Fundamental Theorem of Calculus:<em> if </em>f<em> is a continuous function on </em>[a,b]<em>, then</em>

                                   \int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) |  {_a^b}

where F is an antiderivative of f.

A function F is an antiderivative of the function f if

                                                    F^{'}(x)=f(x)

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x + 15 and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx

\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx

\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2

3 0
3 years ago
Pls answer fast<br> (√3 + √11)² + (√3 - √11)²
Masja [62]

(√3 + √11)² + (√3 - √11)²

  • (a+b)² = a² + b² + 2ab
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<em>Now </em><em>,</em>

(√3 + √11)² + (√3 - √11)²

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Hence , The value of (√3 + √11)² + (√3 - √11)² is 28 .

6 0
2 years ago
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