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Naily [24]
3 years ago
10

A chemist fills a reaction vessel with a 0.105g mercurous chloride Hg2Cl2 solid, 0.926 M mercury (I) (Hg2^2+) aqueous solution,

and 0.573 M chloride (Cl^-) aqueous solution at a temperature of 25.0°C.
Under these conditions, calculate the reaction free energy ΔG for the following chemical reaction:
Hg2Cl2(s) ---->Hg2^2+ (aq) + 2Cl^- (aq)
Chemistry
1 answer:
Hoochie [10]3 years ago
5 0

Answer:

ΔG = 98.67 kJ/mol

Explanation:

Let' s consider the following reaction.

Hg₂Cl₂(s) → Hg₂²⁺(aq) + 2Cl⁻(aq)

The standard Gibbs free energy (ΔG°) for the reaction is:

ΔG° = 1 mol × ΔG°f(Hg₂²⁺(aq)) + 2 mol × ΔG°f(Cl⁻(aq)) - 1 mol × ΔG°f(Hg₂Cl₂(s))

where,

ΔG°f: standard Gibbs free energy of formation

ΔG° = 1 mol × (154.72 kJ/mol) + 2 mol × (-134.08 kJ/mol) - 1 mol × (-215.06 kJ/mol)

ΔG° = 101.62 kJ

This is standard Gibbs free energy change per mole of reaction.

The Gibbs free energy of the reaction (ΔG) can be calculated using the following expression.

ΔG = ΔG° - R.T.lnQ

where,

R: ideal gas constant

T: absolute temperature

Q: reaction quotient

ΔG = ΔG° - R.T.ln([Hg₂²⁺].[Cl⁻]²)

ΔG = 101.62 kJ/mol + (8.314 × 10⁻³ kJ/mol.K) . (298.2 K) . ln [(0.926).(0.573)²]

ΔG = 98.67 kJ/mol

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3 years ago
To what temperature was 32.0L of gas at 2°C be heated for it to occupy 1.00*10^2L at the same pressure?
jolli1 [7]

Answer:

T₂ = 859.4 K

Explanation:

Given data:

Initial volume of gas = 32.0 L

Initial temperature = 2°C (2 + 273 = 275 k)

Final temperature = ?

Final volume = 1.00 ×10²L

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ /V₁  

T₂ = 1.00 ×10²L × 275 K / 32.0 L

T₂ = 27500 L.K / 32.0 L

T₂ = 859.4 K

8 0
4 years ago
cross contamination can it be caused by carrying either drinking glasses by the rims,a plate by its underside surface, utensils
harkovskaia [24]

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3 years ago
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4 0
4 years ago
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A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit
Triss [41]

Answer:

The final pressure is approximately 0.78 atm

Explanation:

The original temperature of the gas, T₁ = 263.0 K

The final temperature of the gas, T₂ = 298.0 K

The original volume of the gas, V₁ = 24.0 liters

The final volume of the gas, V₂ = 35.0 liters

The original pressure of the gas, P₁ = 1.00 atm

Let P₂ represent the final pressure, we get;

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4 0
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