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3 years ago

12

What is -a^-2 if a = -5

1 answer:

astra-53 [7]3 years ago

8 0

Simply substitute the value of a in the question
$-(-5)^{-2} 
$
$5^{-2}$
0.04

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Introduction to Functions: Unit Test

Greeley [361]

Multiples of 8 that are less than 60: 8,16,24,32,40,48,56,
so the 8th run is at 8.4 am ; the 10th run is at 8.20 so u only have to wait a minute.
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6 0

4 years ago

Read 2 more answers

Please help i need this done soon!!

frosja888 [35]

Answer:

f(2) = -2

Step-by-step explanation:

plug in 2 to wherever x is in this statement:

f(2) = -2(2^2) - 2(2) + 10

f(2) = -2(4) - 4 + 10

f(2) = -8 - 4 + 10

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3 years ago

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Find the complement of the set given that

iris [78.8K]

Answer:

A ' = {-2,-1,0,1, 4,7}

Step-by-step explanation:

Here, the Universal set U is given as:

U = {x | x is in I and −3 ≤ x ≤ 7}

⇒ U = { -3,-2,-1,0,1,2,3,4,5,6,7}

Now given: A = {−3, 2, 3, 5, 6}

Compliment A set of any set A is the set of all the elements which is in the universal set U but NOT in A.

So, here the set of elements which are in U but not in A is

A ' = {-2,-1,0,1, 4,7}

So here the elements in the compliment of the given set -2,-1,0,1,4,7

4 0

3 years ago

The roots of x2 -( ) +34 are 5 -/+3i

asambeis [7]

Answer: 10

Step-by-step explanation:

Vieta's formulas :

5 - 3i + 5 + 3i = b ⇒ b =10

Now, we have the equation:

x² -10x + 34 = 0

Mark me brainliest

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3 years ago

A circle has an area of 256 square inches. If the radius of

RSB [31]

Answer:

Option C (4096π in²)

Step-by-step explanation:

Area of the circle = 256π in²

We know that $Area=\pi r^{2}$ , where r = radius of the circle

So,

$256\pi = \pi r^{2}$

Cancelling π from both the sides,

$=> r^{2} = 256$

$=> r = \sqrt{256} = 16$

The radius of the circle = 16 in.

When the radius is multiplied with 4 , new radius = 16×4 = 64 in.

New Area = $\pi (64)^{2} =4096\pi \: in^{2}$

6 0

3 years ago