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Strike441 [17]
3 years ago
9

Help me on this question

Mathematics
1 answer:
lora16 [44]3 years ago
6 0
It's simple, just subtract 3 from 6 because the have the same terms and variables then keep your answer as it should be. you should get 4b³c²+3b²c³
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SOLVE EACH SYSTEM USING SUBSTITUTION
NNADVOKAT [17]
1. since the equations equal each other 
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-x        -x
x+19=7
  -19  -19
x= -12
sub into y= x+7
y= -12+7
y= -5

2. x+2y=-7
<span>x+y+23=0
i don't know what the second equation is equal to, i'll assume 0

2y=x-7
y=1/2x-7/2
sub this into x+y+23=0
x+1/2x-7/2+23=0
3/2x+39/2=0
       -39/2   -39/2
3/2x= -39/2
x=-39/2 / 3/2
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sub into y=1/2x-7/2
y=1/2(-13)-7/2
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3. </span>x+5y=2
<span>x=-4y+5
</span>sub x=-4y+5 into x+5y=2
-4y+5+5y=2
y+5=2
  -5  -5
y= -3
sub y =-3 into x =-4y+5
x=-4(-3)+5
x= 17

4. 3x+y=9
<span>y=-5x+9
</span>sub -5x+9 into 3x+y=9
3x+(-5x+9)=9
3x-5x+9=9
-2x+9=9
     -9  -9
-2x=0
x=0
sub into y=-5x+9
y=-5(0)+9
y=9

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Answer:

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Step-by-step explanation:

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