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valentina_108 [34]

2 years ago

5

Sean biked 20 kilometers on Friday. On Saturday, he biked 0.8 as far. On Sunday, he biked 3 kilometers more than he did on Satur

day.

1 answer:

Ivenika [448]2 years ago

8 0

Answer:

0.11km

Step-by-step explanation:

i hope this helps

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An elevator starts on the 100th floor. It descends 4 floors every 10 seconds. At what floor will the elevator be 60 seconds afte

Artyom0805 [142]

So is 4 floors / 10 seconds
If you have 60 seconds you can multiple 10 by 6 because 10×6=60
so you also have to multiple 4 by 6
4×6=24
and because it's descending it's 100-24= 76

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2 years ago

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Which of the following is a radical equation?<br> x√3=13<br> x+3√3=13<br> √x+3=13<br> x+3=√13

Shtirlitz [24]

The answer would be: <span>√x+3=13

</span>A radical equation is an equation with at least one variable put on a radical form. In this question, there is only one kind of variable which is x. Then, you need to find the equation where x is in the radical form. The radical form can be expressed with square root symbol.
The option with √x would be only <span>√x+3=13
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3 years ago

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50 points! I understand A. and B. but I would really appreciate help with C.

FromTheMoon [43]

Answer:

$51.72\text{ cells per hour}$

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

$P(t)=6.10t^2-9.28t+16.43$

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

$\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]$

Expand:

$P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]$

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

$P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]$

Differentiate. Use the power rule:

$P'(t)=6.10(2t)-9.28(1)$

Simplify:

$P'(t)=12.20t-9.28$

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

$P'(5)=12.20(5)-9.28$

Multiply:

$P'(5)=61-9.28$

Subtract:

$P'(5)=51.72$

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

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2 years ago

X increased by 10 is equal to 42

AysviL [449]

Answer:

x = 32

Step-by-step explanation:

x + 10 = 42, then you subtract 10 from both sides to get 32

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2 years ago

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Using radians, find the amplitude and period of each function.

ELEN [110]

Go to Math Papa that'll give you the answers with the work shown and explanations.

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