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melamori03 [73]

3 years ago

14

Please help me im not good at maths :(((

1 answer:

lapo4ka [179]3 years ago

3 0

Answer:

A) 11% B) 60

Step-by-step explanation:

(for A) if you add all the "Frequency" it adds up to 100, so we don't need to do any maths for that because we already have our 100% right there. So less maths to do because if that right there is already the whole, then the frequency of it is the % out of 100%

(for B) If you take your calculator and do 12 x 500, you get 6,000, press the "%" button and it gives you the percent of what that probability of getting 6 after rolling 500 times with its sent frequency

(took me a minute to learn this this for you... by that i mean i messed around with my calculator for like 3 minutes) Hope this is right.

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Natali [406]

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Ne4ueva [31]

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3 years ago

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3 years ago

Jim's backyard is a rectangle that is 15 5/6 yards long and 10 2/5 yards wide. Jim buys sods in pieces that are 1 1/3 yards long

Ne4ueva [31]

We are given

Jim's backyard:

Length is

$L=15\frac{5}{6} =\frac{95}{6} yards$

width is

$W=10\frac{2}{5} =\frac{52}{5} yards$

Since, this is rectangle

so, we can find area of rectangle

$A=L*W$

$A=(\frac{95}{6})*(\frac{52}{5})$

$A=\frac{494}{3} yard^2$

Area of one sod:

length is

$l=1\frac{1}{3} =\frac{4}{3} yards$

width is

$w=1\frac{1}{3} =\frac{4}{3} yards$

Since, it is rectangle in shape

so,

$Area=l*w$

$A=\frac{4}{3}*\frac{4}{3}$

$A=\frac{16}{9}yard^2$

Number of pieces of sod:

we can use formula

Number of pieces of sod = (area of Jim's backyard)/(area of one sod)

$N=\frac{\frac{494}{3} }{\frac{16}{9} }$

now, we can simplify it

$N=\frac{741}{8}$ pieces need ..............Answer

7 0

3 years ago