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mash [69]
3 years ago
12

3/7 is proper, improper, or mixed number

Mathematics
2 answers:
padilas [110]3 years ago
5 0
It is a proper fraction.
An example of an improper fraction is 10/4 because the numerator is bigger than the denominator.
An example of a mixed number is 4 5/7
So 3/7 is proper.
luda_lava [24]3 years ago
3 0

Answer:

Proper

Step-by-step explanation:

An improper fraction has a greater numerator than denominator, a mixed number has a whole number next to it. If the numerator is less than the denominator and there are no whole numbers next to it, the fraction is proper.

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A math book comprises of 2 sections: arithmetic and geometry in the ratio 5:3. How much of each type of content will be needed t
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What are all values of x for which the series shown converges? ​
adoni [48]

Answer:

One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:

Iaₙ₊₁I < IaₙI

This means that the absolute value of the terms must decrease as n increases.

Then we must have:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}

We can write this as:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}

If we assume that n is a really big number, then:

n + 1 ≈ 1

And we can write:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}

Then we have the inequality

1 > (x - 2)/3

And remember that this must be in absolute value, then we will have that:

-1 < (x - 2)/3 < 1

-3 < x - 2 < 3

-3 + 2 < x < 3 + 2

-1 < x < 5

The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.

5 0
3 years ago
What did Zorna say about marrying a shorter man?
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5 0
3 years ago
Help mi out plz..... solve using matrix method​
HACTEHA [7]

Answer:

x = \frac{22}{7}

y = \frac{3}7}

Step-by-step explanation:

2x-3y=5\\5x=4y=14\\\\\left[\begin{array}{cc}2&-3\\5&-4\\\end{array}\right] \left[\begin{array}{c}x\\y\\\end{array}\right] =\left[\begin{array}{c}5\\14\\\end{array}\right]

Let A = \\\left[\begin{array}{cc}2&-3\\5&-4\\\end{array}\right]

The inverse of A multiplied by A = the identity matrix \left[\begin{array}{cc}1&0\\0&1\\\end{array}\right]

Inverse of A = \frac{1}{detA} \left[\begin{array}{ccc}-4&3\\-5&2\\\end{array}\right]

detA = ad - bc = -8 - - 15 = 7

Inverse of A = \left[\begin{array}{cc}\frac{-4}{7} &\frac{3}{7} \\\frac{-5}{7} &\frac{2}{7}\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{cc}\frac{-4}{7} &\frac{3}{7} \\\frac{-5}{7} &\frac{2}{7}\\\end{array}\right] \left[\begin{array}{ccc}5\\14\\\end{array}\right] = \left[\begin{array}{ccc}\frac{22}{7} \\\frac{3}{7} \\\end{array}\right]

5 0
3 years ago
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