Answer:
9/10
Step-by-step explanation:
Answer:
<em>There are approximately 114 rabbits in the year 10</em>
Step-by-step explanation:
<u>Exponential Growth
</u>
The natural growth of some magnitudes can be modeled by the equation:

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.
We are given two measurements of the population of rabbits on an island.
In year 1, there are 50 rabbits. This is the point (1,50)
In year 5, there are 72 rabbits. This is the point (5,72)
Substituting in the general model, we have:

![50=P_o(1+r)\qquad\qquad[1]](https://tex.z-dn.net/?f=50%3DP_o%281%2Br%29%5Cqquad%5Cqquad%5B1%5D)
![72=P_o(1+r)^5\qquad\qquad[2]](https://tex.z-dn.net/?f=72%3DP_o%281%2Br%29%5E5%5Cqquad%5Cqquad%5B2%5D)
Dividing [2] by [1]:

Solving for r:
![\displaystyle r=\sqrt[4]{\frac{72}{50}}-1](https://tex.z-dn.net/?f=%5Cdisplaystyle%20r%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B72%7D%7B50%7D%7D-1)
Calculating:
r=0.095445
From [1], solve for Po:



The model can be written now as:

In year t=10, the population of rabbits is:

P = 113.6

There are approximately 114 rabbits in the year 10
oh shi sorry I wish I could help but I'm stupid
Answer:
C. Three
Step-by-step explanation:
We want to solve the equation for n:
14,580 = 20,000(9/10)^n
14580/20000 = 729/1000 = (9/10)^n
(9/10)^3 = (9/10)^n . . . . . . write the left side as a cube
3 = n . . . . . . equate exponents
After year 3, the value will be $14,580.
_____
You can use logarithms to find n:
log(0.729) = n×log(0.9) . . . . . . taking the log of the 2nd line above
log(0.729)/log(0.9) = n = 3