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Bogdan [553]
3 years ago
6

A powerboat, starting from rest, maintains a constant acceleration. After a certain time 't', its displacement and velocity are

'r' and 'v'. At time '2t', what will be its displacement and velocity, assuming the acceleration remains constant?
a) 2r and 2v
b) 2r and 4v
c) 4r and 2v
d) 4r and 4v
Physics
1 answer:
EastWind [94]3 years ago
6 0

Answer: Ok, so you know the acceleration, lets call it A.

now, the velocity will take the form of V= A*t + v0, where v0 is the inicial velocity, in this case the boat starts from the rest, so v0 = 0

integrating again you obtain R = (A*t*t)/2 + r0, and we will take r0 = 0.

so, at a time t₁ we have a velocity V = v = A*t₁

                                                           R = r = (A*t₁*t₁)/2

so a t₂=2*t₁

V= A*2*t₁= 2v

R= 0.5*A*t₁*t₁*4 = 4r

so the answer is c.

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Answer:

Explanation:

Experts in this field report that the modulation is FM or frequency modulation. There are exceptions, but they were not listed.

The usual frequencies allocated to these toys is 27 MHz and 72 Mhz.

There is not much chance of interference because the range is small even with a good transmitter.

3 0
3 years ago
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2) What does the specific heat capacity of a material tell you about how easy it is to heat up
Fed [463]

Answer:

High specific heat -> takes more energy to raise/lower object's temperature

Low specific heat -> takes less energy to raise/lower object's temperature

Explanation:

The specific heat capacity is the amount of heat required to raise the temperature of something per unit of mass.

A high specific heat value for an object means it takes more energy to raise or lower that object's temperature. A low specific heat value for an object means it does not take very much energy to heat or cool that object.

6 0
3 years ago
Light from a helium-neon laser (λ=633nm) passes through a circular aperture and is observed on a screen 4.0 m behind the apertur
devlian [24]

Answer:

d = 0.247 mm

Explanation:

given,

λ = 633 nm

distance from the hole to the screen = L = 4 m

width of the central maximum = 2.5 cm

                                             2 y = 0.025 m

                                               y = 0.0125 m

For circular aperture

  sin \theta = 1.22\dfrac{\lambda}{d}

using small angle approximation

  \theta = \dfrac{y}{D}

now,

   \dfrac{y}{D} = 1.22\dfrac{\lambda}{d}

   y = 1.22\dfrac{\lambda\ D}{d}

   d = 1.22\dfrac{\lambda\ D}{y}

   d = 1.22\dfrac{633\times 10^{-9}\times 4}{0.0125}

         d =0.247 x 10⁻³ m

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the diameter of the hole is equal to 0.247 mm

5 0
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5 0
4 years ago
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A proton moves at constant velocity in the direction, through a region in which there is an electric field and a magnetic field.
dimaraw [331]

Answer:

F_{net}=0

Explanation:

It is given that, a proton moves at constant velocity, through a region in which there is an electric field and a magnetic field such that,

The electric field is, E = 800 V/m

Magnetic field, B = 0.25 T

We know that the net force in the region of magnetic and electric field is given by Lorentz forces. But here, the proton moves with constant velocity. So, the net force acting on it is 0.

i.e.

F_{net}=0

Hence, this is the required solution.

7 0
3 years ago
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