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3 years ago

7

You are on an airplane that is landing. The plane in front of your plane blows a tire. The pilot of your plane is advised to abo

rt the landing, so he pulls up, moving in a semicircular upward-bending path. The path has a radius of 450 m with a radial acceleration of 17 m/s^2.
Required:
What is the plane's speed?

1 answer:

Andrei [34K]3 years ago

4 0

Answer:

v = 87.46 m/s

Explanation:

The radial acceleration is the centripetal acceleration, whose formula is given as:

$a_c = \frac{v^2}{r}$

where,

$a_c$ = centripetal acceleration = 17 m/s²

v = planes's speed = ?

r = radius of path = 450 m

Therefore,

$17\ m/s^2 = \frac{v^2}{450\ m}\\\\v^2 = (17\ m/s^2)(450\ m)\\\\v = \sqrt{7650\ m^2/s^2}$

<u>v = 87.46 m/s</u>

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