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bixtya [17]
3 years ago
7

You are on an airplane that is landing. The plane in front of your plane blows a tire. The pilot of your plane is advised to abo

rt the landing, so he pulls up, moving in a semicircular upward-bending path. The path has a radius of 450 m with a radial acceleration of 17 m/s^2.
Required:
What is the plane's speed?
Physics
1 answer:
Andrei [34K]3 years ago
4 0

Answer:

v = 87.46 m/s

Explanation:

The radial acceleration is the centripetal acceleration, whose formula is given as:

a_c = \frac{v^2}{r}

where,

a_c = centripetal acceleration = 17 m/s²

v = planes's speed = ?

r = radius of path = 450 m

Therefore,

17\ m/s^2 = \frac{v^2}{450\ m}\\\\v^2 = (17\ m/s^2)(450\ m)\\\\v = \sqrt{7650\ m^2/s^2}

<u>v = 87.46 m/s</u>

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the focal length of a simple magnifier is 8.50 cmcm . assume the magnifier to be a thin lens placed very close to the eye.
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Angular magnification:

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