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3 years ago

Pleaseeee help!!!!!!!!

Physics

1 answer:

kenny6666 [7]3 years ago

6 0

Most likely B. Will erode, if not it will grow weeds

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What's the average speed of an object moving 3790 meters in 249 s.

NISA [10]

Heya!!

For calculate velocity, lets applicate formula

$\boxed{d = v * t}$

Δ Being Δ

d = Distance = 3790 m

t = Time = 249 s

v = Velocity = ?

⇒ Let's replace according the formula and clear "v":

$\boxed{v= 3790\ m / 249\ s}$

⇒ Resolving

$\boxed{ v = 15,22 \ m/s }$

Result:

The velocity is 15,22 meters per second.

Good Luck!!

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3 years ago

A solid 0.4550 kg ball rolls without slipping down a track toward a vertical loop of radius R = 0.6750 m . What minimum translat

Talja [164]

Answer:

u = 3.35 m/s

Explanation:

given,

mass , m = 0.455 kg

R = 0.675 m

Height of Loop = 1.021 m

the speed required at the top of loop be v

equating the force vertically

$m g =\dfrac{mv^2}{r}$

$9.81 =\dfrac{v^2}{0.675}$

v² = 6.622

v = 2.57 m/s

Let the initial speed of ball be u

using conservation of energy

$\dfrac{1}{2}mu^2 + \dfrac{1}{2}I\omega^2 + m g h = \dfrac{1}{2}I\omega^2 + \dfrac{1}{2}mv^2+ m g (2 R)$

where, $I =\dfrac{2}{5}mr^2$

$\dfrac{1}{2}mu^2 + \dfrac{1}{2}(\dfrac{2}{5}mr^2)(\dfrac{u}{r})^2 + m g h = \dfrac{1}{2}(\dfrac{2}{5}mr^2)(\dfrac{v}{r})^2 + \dfrac{1}{2}mv^2+ m g (2 R)$

$0.7 u^2 + g H = 0.7 v^2 + g(2R)$

$0.7 u^2 +9.81 \times 1.021= 0.7\times 2.57^2 + 9.81 \times 2\times 0.675)$

0.7 u² = 7.85092

u² = 11.2156

u = 3.35 m/s

the initial speed is 3.35 m/s

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3 years ago

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Tema [17]

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i think i hope this example helps you somehow srry that i dont know more then that :/

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Answer:

Its a social media platform

Explanation:

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