Answer:
moving at a constant rate. (could be zero m/s)
Answer:
(a)
, 
(b) When
, object is slowing down, when
object is speeding up.
Explanation:
(a) To get the velocity function, we need to take the derivative of the position function.

To get the acceleration function, we need to take the derivative of the velocity function.

(b) The object is slowing down when velocity is decreasing by time (decelerating) hence a < 0

On the other hand, object is speeding up when a > 0

Therefore, when
, object is slowing down, when
object is speeding up.
The average distance from the Sun to Neptune is about 2.795 billion miles.
That's roughly 0.00048 of a light year .
It starts as a igneous rock and becomes metamorphic then sedimentary