Answer:
(a) 
(b) 
Given:
Time period of Pulsar, 
Equatorial radius, R = 15 Km = 15000 m
Spinning time, 
Solution:
(a) To calculate the value of the centripetal acceleration, 
on the surface of the equator, the force acting is given by the centripetal force:
(1)
where
(2)
Now, from (1) and (2):
(b) To calculate the tangential acceleration of the object :
The tangential acceleration of the object will remain constant and is given by the equation of motion as:
where
u = 
Answer:
So visible wavelength which is possible here is
416 nm and 693.3 nm
Explanation:
As we know that for normal incidence of light the path difference of the reflected ray is given as
so here we can say that for maximum intensity condition we will have
so we have
now for visible wavelength we have
for N = 1
for N = 2
for N = 3
Gravity is the force that attracts to bodies toward each other friction is the resistance from one thing to another
<h2>Greetings!</h2>
Firstly, to find speed you need to remember the speed formula:
Speed = Distance ÷ Time
You can do it by doing 2800 ÷ 2 but that gives m/h (metres per hour)
So to convert hours into seconds, you multiply 2 by 7200 (amount of second in 2 hours:
2 * 7200 = 14400 seconds
Now we can do distance ÷ time by plugging the values in:
2800 ÷ 14400 = 
≈0.194
<h3>So the average speed is 0.194m/s (metres per second) </h3><h3 /><h2>Hope this helps!</h2>
