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Drupady [299]
3 years ago
12

Earth has a mass of 5,970,000,000,000,000,000,000,000 kg. How would

Physics
1 answer:
mr Goodwill [35]3 years ago
7 0

Answer:

5.97×10^24 kg

Explanation:

thats how it is expressed

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Help with physical science please
alex41 [277]

1. Elastic potential energy (D. EEl)

In this situation, the spring is compressed with the toy on top of it. The toy is stationary, so it does not have kinetic energy. However, the spring is compressed, so it does have elastic potential energy, given by:

E_{EL}=\frac{1}{2}kx^2

where k is the spring constant and x is the compression of the spring.

2. Gravitational potential energy (C. Eg)

In this situation, the spring has been released, so it returns to its natural position, so its elastic potential energy is zero. The toy is also stationary, since it is at its top position, where its velocity is zero, so its kinetic energy is also zero. However, the toy is now at a certain height h above the spring, so it has gravitational potential energy given by:

E_g = mgh

where m is the mass of the toy and g is the gravitational acceleration.

3. Gravitational potential and kinetic energy (A. Eg and EK)

In this situation, the toy is falling: so, it is moving with a certain speed v, so it has kinetic energy given by

E_k = \frac{1}{2}mv^2

Also, since it is at a certain height above the spring, it still has some gravitational potential energy, as in the previous point.

4. Gravitational potential energy (C. Eg)

The jumper is standing on the bridge, so it has gravitational potential energy given by its height h above the ground:

E_g=mgh

where m is the mass of the jumper.

5. This exercise has the same text of the previous one.

8 0
3 years ago
A rocket sled accelerates at a rate of 49.0 m/s2 . Its passenger has a mass of 75.0 kg. (a) Calculate the horizontal component o
Katen [24]

Explanation:

It is given that,

Mass of the passenger, m = 75 kg

Acceleration of the rocket, a=49\ m/s^2

(a) The horizontal component of the force the seat exerts against his body is given by using Newton's second law of motion as :

F = m a

F=75\ kg\times 49\ m/s^2

F = 3675 N

Ratio, R=\dfrac{F}{W}

R=\dfrac{3675}{75\times 9.8}=5

So, the ratio between the horizontal force and the weight is 5 : 1.

(b) The magnitude of total force the seat exerts against his body is F' i.e.

F'=\sqrt{F^2+W^2}

F'=\sqrt{(3675)^2+(75\times 9.8)^2}

F' = 3747.7 N

The direction of force is calculated as :

\theta=tan^{-1}(\dfrac{W}{F})

\theta=tan^{-1}(\dfrac{1}{5})

\theta=11.3^{\circ}

Hence, this is the required solution.

8 0
4 years ago
you stand on a straight desert road at night and observe a vehicle approaching. this vehicle is equipped with two small headligh
inysia [295]

Answer:

The distance that you marginally able to discern that there are two headlights rather than a single light source is 6.084 km

Explanation:

Given:

d = distance = 0.679 m

λ = wavelength of the light = 537 nm = 537x10⁻⁹m

dp = pupil diameter = 4.81 mm = 0.00481 m

Question: What distance, in kilometers, are you marginally able to discern that there are two headlights rather than a single light source, dx = ?

For the separation of the peak from the central maximum it is:

sin\theta =\frac{\lambda }{d_{p} } =\frac{537x10^{-9} }{0.00481} =1.116x10^{-4}

In this case, the two small sources of the headlights have the same angle as the images that form inside the eye

d_{x} =\frac{d}{sin\theta } =\frac{0.679}{1.116x10^{-4} } =6.084x10^{3} m=6.084km

7 0
4 years ago
A book is being pushed to the right across a desk with a constant acceleration.
nexus9112 [7]

Explanation:

The force would be net positive.

7 0
3 years ago
If you wanted to get yellow light , what part of the of the spectrum would the color filter have to absorb ?
densk [106]
The filter would need to absorb every color EXCEPT yellow. It would have to absorb red orange green blue and violet.
4 0
3 years ago
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