Answer:
16.67 rad/s
Explanation:
if you read the question, you would notice that some requirements are missing, while searching online, the complete question can be found here:
https://www.chegg.com/homework-help/questions-and-answers/frictionless-pulley-modeled-080-solid-cylinder-030-m-radius-rope-going--tension-rope-10-n--q3499646
and here is the complete question:
"a frictionless pulley which can be modeled as a 0.80 solid cylinder with a 0.30 m radius has a rope going over it. The tension in the rope is 10 N on the right side and 12 N on the left side. What is the angular acceleration of the pulley?
"
mass (m) = 0.8 kg
radius (r) = 0.3 m
tension on left side (T1) = 10 N
tension on right side (T2) = 12 N
angular acceleration = torque / moment of inertia
where
torque = (12-10) x 0.3 = 0.6 Nm
- moment of inertia = 0.5m
moment of inertia = 0.5 x 0.8 x = 0.036 kg
therefore
angular acceleration = 0.6/0.036 = 16.67 rad/s
Alpha Centauri A is about 93 million miles away from the Earth and it takes light 4.367 years to reach there.
Answer:
Explanation:
Two forces are 10 N and 30 N. Let us assume that two forces are acting in opposite directions. Net force will be :
F = 30 N - 10 N = 20 N
Now,
F = ma
⇒ a = F/m
So,
So, the acceleration of the object is .
22.5 J
Explanation:
Given:
x = 3 m
The spring potential energy is
d=18cm=0.18m thickness of board
vi=420m/s speed before entering the board
vf=320m/s speed when leaving the board
vf²=vi²+2×a×d
Acceleration a=(vf²-vi²)/2/d
a=-205.5m/s².
As expected, a is negative because the bullet is decelerated.
vf=vi+a×t
t=(vf-vi)/a=(320-420)/(-205.5)= 100/205.5=0.486s
t=0.486s=486ms