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3 years ago

4.

Physics

1 answer:

Nezavi [6.7K]3 years ago

7 0

The density of an object remains same irrespective of its shape, size and quantity.

Explanation:

Density is an intensive property. This means that regardless of the object's shape, size, or quantity, the density of that substance will always be the same. Even if you cut the object into a million pieces, they would still each have the same density. It is because density in an intensive property of matter.

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What is the difference between speed and velocity? A. Velocity takes acceleration into account, while speed does not. B. Speed t

nalin [4]

C!

V= displacement/time
Speed= distance/time

Displacement is the space between two points, usually from the first to last point, but doesn't have to be. (Basically, it's the distance between your starting and ending point). With displacement, direction matters, but with speed, direction doesn't.

Speed, on the other hand, is the entire traveled distance as a whole. Unlike displacement, direction doesn't matter.

I hope this helped!

5 0

4 years ago

Hi people; there's a question that has been so confusing for me and a friend of mine.

Alborosie

Answer:

The correct answer is: 0°C + 0°C = 32°F

Explanation:

We need to remember the conversion equation from Celsius to Fahrenheit:

$y^{\circ}F=(x^{\circ}C * \frac{9}{5})+32$

In our case x = 0, then y will be:

$(0^{\circ}C * \frac{9}{5})+32=32$

$y=32^{\circ}F$

Now 0°C + 0°C is just 0°C because if we add a body at a certain temperature to another body with the same temperature the total temperature will the same.

Then, knowing that 0°C = 32°F we can conclude that:

$0^{\circ}C+0^{\circ}C=32^{\circ}F$

I hope it helps you!

7 0

4 years ago

Evaluate how a reduction in the number of condensation nuclei in the tropo-

marta [7]

Answer:

i do not no sory

Explanation:

6 0

3 years ago

An electric motor rotating a workshop grinding wheel at a rate of 1.31 ✕ 102 rev/min is switched off. Assume the wheel has a con

antoniya [11.8K]

(a) 4.03 s

The initial angular velocity of the wheel is

$\omega_i = 1.31 \cdot 10^2 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=13.7 rad/s$

The angular acceleration of the wheel is

$\alpha = -3.40 rad/s^2$

negative since it is a deceleration.

The angular acceleration can be also written as

$\alpha = \frac{\omega_f - \omega_i}{t}$

where

$\omega_f = 0$ is the final angular velocity (the wheel comes to a stop)

t is the time it takes for the wheel to stop

Solving for t, we find

$t=\frac{\omega_f - \omega_i }{\alpha}=\frac{0-13.7 rad/s}{-3.40 rad/s^2}=4.03 s$

(b) 27.6 rad

The angular displacement of the wheel in angular accelerated motion is given by

$\theta= \omega_i t + \frac{1}{2}\alpha t^2$

where we have

$\omega_i=13.7 rad/s$ is the initial angular velocity

$\alpha = -3.40 rad/s^2$ is the angular acceleration

t = 4.03 s is the total time of the motion

Substituting numbers, we find

$\theta= (13.7 rad/s)(4.03 s) + \frac{1}{2}(-3.40 rad/s^2)(4.03 s)^2=27.6 rad$

6 0

3 years ago

The force of gravity pulls down on your school with a total force of 400,000 newtons. The force of gravity pulling down on your

Marina CMI [18]

Explanation:

It is given that, the force of gravity pulls down on your school with a total force of 400,000 N.

The force of gravity is given by the formula as follows :

F = mg

m is mass and g is the acceleration due to gravity

Mass of an object remains same always. But if the mass of your school becomes twice of the initial mass, the force of gravity pulling down on your school would be exactly twice.

4 0

3 years ago