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Stells [14]
3 years ago
15

The capacitor in the flash of a disposable camera has a value of 165 μF. 1) What is the resistance of the filament in the bulb i

f it takes 10 s to charge the capacitor to 80% of its maximum charge? (Express your answer to two significant figures.)
Physics
1 answer:
pashok25 [27]3 years ago
7 0

Answer:

3.8 x 10⁴ Ω

Explanation:

C = Capacitance = 165 μF

R = resistance of the filament = ?

t = time taken to charge the capacitor = 10 s

Q₀ = maximum charge stored by capacitor

Q = charge stored by capacitor at time "t" = 0.80 Q₀

T = Time constant

Charge stored by capacitor at any time is given as

Q = Q_{o}(1 - e^{\frac{-t}{T}})

0.80 Q_{o} = Q_{o}(1 - e^{\frac{-10}{T}})

T = 6.21 s

Time constant is given as

T = RC

6.21 = R (165 x 10⁻⁶)

R = 3.8 x 10⁴ Ω

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