Answer:
x≤ 9
Step-by-step explanation:
add 6 to the other side to get x by itself....
Answer:
5th term will approximate 5461/64
Step-by-step explanation:
5th term will approximate 5461/64
64+16+4+1+0.25 = 85.25 ≈ 5461/64 = 85.33
Answer:
The half-life of the radioactive substance is 135.9 hours.
Step-by-step explanation:
The rate of decay is proportional to the amount of the substance present at time t
This means that the amount of the substance can be modeled by the following differential equation:

Which has the following solution:

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.
After 6 hours the mass had decreased by 3%.
This means that
. We use this to find r.







So

Determine the half-life of the radioactive substance.
This is t for which Q(t) = 0.5Q(0). So







The half-life of the radioactive substance is 135.9 hours.
A=r^ 2 * pi=35^ 2 *3.14=3846.5m
-4x + 7y = -8 . . . (1)
-5x + 6y = 1 . . . .(2)
(1) x 5 => -20x + 35y = -40 . . . (3)
(2) x 4 => -20x + 24y = 4 . . . . .(4)
(3) - (4) => 11y = -44 => y = -44/11 = -4
From (2), -5x + 6(-4) = 1 => -5x - 24 = 1 => -5x = 1 + 24 = 25 => x = 25/-5 = -5
Therefore, x = -5, y = -4