The arrangement of homeotic genes along chromosomes of vertebrate and invertebrate animals corresponds to the expression pattern of the genes along the anterior-posterior axis of the developing embryo.
<h3>What are homeotic genes?</h3>
- Homeotic genes are a group of body pattern forming genes which control the development along the anterior- posterior axis of the developing embryo.
- These encode transcription factors which control and specify the genes involved in body patterning. These provide identity to the segments during embryo formation.
- Genes located in the 5’ end act on posterior side whereas the genes on 3’ end act on anterior region.
- Homeotic genes are evolutionary conserved and control body specification, patterning and differentiation.
- The loss of function of any of the gene changes the body pattern and affects the development.
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Answer:
setting regulations for trains carrying cargo
Explanation:
USMA is the United States Military Academy in the West point. This academy provides a bachelor of science degree along with a cadet's performance in military and athletic activities.
USMA control diferrent functions in West Point and one of them is setting regulations for trains carrying cargo. USMA controls the department of defense and is responsible for making rules and regulation related to the trains carrying cargo.
Hence, the correct answer is "setting regulations for trains carrying cargo".
Explanation:
The genes that determine color and pattern are linked.
- Solid pattern allele (L) is dominant over lined pattern (l)
- Blue color allele (B) is dominant over aqua color (b)
<h3><u>Initial cross</u></h3>
Homozygous lined aqua beetle has the genotype <em>lb/lb</em>
It can produce only 1 type of gamete: <em>lb</em>
X
Homozygous solid blue beetle has the genotype<em> </em><em>LB/LB</em>
It can produce only 1 type of gamete:<em> </em><em>LB</em>
The F1 is formed by the union of the parents' gametes, so it will have the genotype <em>lb/LB</em>
<h3><u>F1 test cross</u></h3>
Test crosses involve a homozygous recessive individual.
<u>The homozygous recessive individual</u><u><em> lb/lb</em></u><u> can only produce 1 type of gamete:</u>
<u>The F1 individual </u><em><u>lb/LB</u></em><u> can produce 4 types of gametes:</u>
- lb - parental
- LB - parental
- lB - recombinant
- Lb - recombinant
The right answer is 5.
To answer this question it is sufficient to take the same approach as the one that concluded that each amino acid is equivalent to 3 codons.
We have 17 amino acids, each of which must have at least one unique code (having two nucleotides A and T)
.
it is enough to apply this time to count the number of possible codons to be generated according to the number of nucleotides:
nucleotide set ^ number of nucleotides = number of codons
.
2 ^ 1 = 2 (<17)
2 ^ 2 = 4 (<17)
2 ^ 3 = 8 (<17)
2 ^ 4 = 16 (<17)
2 ^ 5 = 32 (> 17)
So, each amino acid has a codon of 5 nucleotides.
