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3 years ago

I STILL NEED HELP YALL GOTTA WORK WITH ME SRRY :( (..GIMMIE SUM ANSWERS) 8th grade

Mathematics

1 answer:

crimeas [40]3 years ago

4 0

1) In the box, we are given two points: (10,7) and (25,17.5).

2) Using these points (and the equation y2-y1/x2-x1), we know that this slope is 0.7 or 7/10.

3) y=0.7x

4) Plug 50 into the equation: y=0.7(50) = 35

Answer

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Olegator [25]

Answer:

They are not similar.

Step-by-step explanation:

To find whether or not they are similar, set them up as a proportion.

(2.4/5.2) = (8/13)

Now cross multiply.

2.4*13 = 5.2*8

31.2 = 41.6

Since they are not exact, they are not similar.

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4 years ago

8. Expand, then simplify: (2 Points) (2a – 3) (a2 + 3a - 5)

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3 years ago

HELP PLEASE IM STUCK

Ludmilka [50]

A. y=180-15m
m is the number of months. 180 is the amount owed after the down payment was made.
B. X intercept (12,0)
Y intercept (0,180)
X intercept is the number of months until the tv is paid off. The y intercept is the amount owed after the down payment is made. How much they will be making payments on.
32. 5x + 15

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3 years ago

A simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute

Katyanochek1 [597]

Answer:

Step-by-step explanation:

Given that:

sample size n = 36

standard deviation = 10.1

level of significance ∝ = 0.10

The null hypothesis and the alternative hypothesis can be computed as follows:

$H_0 : \sigma = 10$

$H_1 : \sigma \neq 10$

The test statistics can be computed as follows:

$X^2 = \dfrac{(n -1)s^2 }{\sigma ^2}$

$X^2 = \dfrac{(36 -1)10.1^2 }{10^2}$

$X^2 = \dfrac{(35)102.01 }{100}$

$X^2 = \dfrac{3570.35 }{100}$

$X^2 =35.704$

degree of freedom = n - 1 = 36 - 1 = 35

Since this test is two tailed .

The P -value can be determined by using the EXCEL FUNCTION ( = 2 × CHIDIST(35.7035, 35)

P - value = 2 × 0.435163515

P - value = 0.8703 ( to four decimal places)

Decision Rule : To reject the null hypothesis if P - value is less than the 0.10

Conclusion: We fail to reject null hypothesis ( accept null hypothesis) since p-value is greater than 0.10 and we conclude that there is sufficient claim that the normal range of pulse rates of adults given as 60 to 100 beats per minute resulted to a standard deviation of 10 beats per minute.

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