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mezya [45]
2 years ago
6

A bicycle racer inflates their tires to 7.1 atm on a warm autumn afternoon when temperatures reached 27 °C. By morning the tempe

rature has dropped to 5.0 °C. What is the pressure (in atm) in the tires if we assume that the volume of the tire does not change?
Physics
1 answer:
natulia [17]2 years ago
8 0

Answer:

The required pressure is 6.4866 atm.

Explanation:

The given data : -

In the afternoon.

Initial pressure of tire ( p₁ ) = 7 atm = 7 * 101.325 Kpa =  709.275 Kpa

Initial temperature ( T₁ ) = 27°C = (27 + 273) K = 300 K

In the morning .

Final temperature ( T₂ ) = 5°C = ( 5 + 273 ) K = 278 K

Given that volume remains constant.

To find final pressure ( p₂ ).

Applying the ideal gas equation.

p * v = m * R * T

\frac{p}{T}  = constant

\frac{p_{1} }{T_{1} }  = \frac{p_{2} }{T_{2} }

p_{2}  = \frac{T_{2} }{T_{1} } *p_{1}  

p_{2}  = \frac{278}{300}  * 709.275  = 657.2615 Kpa = 6.486 atm

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First we have to calculate the volume of the living room:
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Answer:

Approximate linear dimension is 2 light years.

Explanation:

Radius of the spiral galaxy r = 62000 LY

Thickness of the galaxy h = 700 LY

Volume of the galaxy = πr²h

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Since galaxy contains number of stars = 1078 billion stars ≈ 1.078\times 10^{12}

Now volume covered by each star of the galaxy = \frac{\text{Total volume of the galaxy}}{\text{Number of stars}}

= \frac{8.45\times 10^{12} }{1.078\times 10^{12}}

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= 1.99 LY

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Therefore, approximate linear dimension is 2 light years.

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