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Nataly [62]
3 years ago
11

Magnetic field lines begin at the _?_ pole of a magnet and end at the _?_ pole

Physics
1 answer:
Basile [38]3 years ago
6 0
North Pole and South Pole
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The amount of heat that is needed to raise the temperature of 1
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a. specific heat

Explanation:

a. specific heat

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Taylor places a nail on a bar magnet. The nail sticks to the magnet when lifted up off the table. She touches a paperclip to the
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Prior to touching the bar magnet, the magnetic domains in the nail were pointing in random directions. When Taylor touched the nail to the bar magnet the magnetic fields of the magnetic domains aligned and it became a temporary magnet.
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X-rays with an energy of 86 keV scatter off of stationary electrons. How much energy do the photons scattering at 60° have? A. 7
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Answer:

A. 79.3 keV

Explanation:

Because the procedure involves many steps for its resolution and it works faster on paper and pencil, the detailed solution of this exercise is attached as a scanned image of the procedure for review.  

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3 years ago
An ordinary workshop grindstone has a radius of 7.50 cm and rotates at 6500 rev/min. (a) Calculate the magnitude of the centripe
jonny [76]

To solve this problem it is necessary to apply the concepts related to the relationship between tangential velocity and centripetal velocity, as well as the kinematic equations of angular motion. By definition we know that the direction of centripetal acceleration is perpendicular to the direction of tangential velocity, therefore:

a_c= \frac{v^2}{r}=r\omega^2

Where,

V = the linear speed

r = Radius

\omega = Angular speed

The angular speed is given by

\omega =6500\frac{rev}{min}(\frac{2\pi rad}{1 rev})(\frac{1 min}{60s})

\omega = 680.6784 rad/s.

Replacing at our first equation we have that the centripetal acceleration would be

a_c = r\omega^2

a_c = (0.0750)(680.6784)^2

a_c = 34 749.23 m/s^2

To transform it into multiples of the earth's gravity which is given as 9.8m / s the equivalent of 1g.

a_c =34749.23 \frac{m}{s^2} (1\frac{g}{9.8m/s^2})

a_c = 3545.84g

PART B) Now the linear speed would be subject to:

v = \omega r

v= (680.6784)(0.0750)

v=51.05 m/s

Therefore the linear speed of a point on its edge is 51.05m/s

8 0
3 years ago
A 1-liter root beer bottle is immersed halfway in water.What is the buoyant force on the bottle?
Dennis_Churaev [7]

mass of one liter of water= 1kg

Archimedes says:

F= m g = 1 kg* 9.81 m/s^2 = 9.81 newtons

7 0
3 years ago
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