The maximum transverse acceleration of an element of this string is 375 m/s
<h3>What is the maximum transverse acceleration?</h3>
For a transverse wave, the velocity is known to be perpendicular to the direction of the propagation of the particular wave. To get the acceleration, what is necessary is to take the partial derivative as it compares to time and the velocity.
With this in mind, we would have
transverse acceleration
a(t) = d²y/dt² = -0.150*50.02sin(0.8x - 50t)
= 0.150*502 = 375 m/s2
Hence we can say that the maximum acceleration of the element on the string is given as 375 m/s²
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