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FinnZ [79.3K]
1 year ago
9

A sinusoidal wave in a string is described by the wave functiony=0.150 sin (0.800x - 50.0t)where x and y are in meters and t is

in seconds. The mass per length of the string is 12.0 g/m(a) Find the maximum transverse acceleration of an element of this string
Physics
1 answer:
AleksAgata [21]1 year ago
6 0

The maximum  transverse acceleration of an element of this string is 375 m/s

<h3>What is the  maximum transverse acceleration?</h3>

For a transverse wave, the velocity is known to be perpendicular to the direction of the propagation of the particular wave. To get the acceleration, what is necessary is to take the partial  derivative as it compares to time and the velocity.

With this in mind, we would have

transverse acceleration

a(t) = d²y/dt² = -0.150*50.02sin(0.8x - 50t)

= 0.150*502 = 375 m/s2

Hence we can say that the maximum acceleration of the element on the string is given as 375 m/s²

Read more on acceleration here

brainly.com/question/605631

#SPJ4

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a hippopotamus produces a pressure of 250000 pa when it is standing on all four feet if the weight of the hippo is 40000 N what
mamaluj [8]

0.04m²

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8 0
3 years ago
Through what potential difference would you need to accelerate an alpha particle, starting from rest, so that it will just reach
Svetlanka [38]

Answer:

\Delta V    = 1.8 \times 10^7 V

Explanation:

GIVEN

diameter = 15 fm  =15 \times 10^{-15}m

we use here energy conservation

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there will be some initial kinetic  energy but after collision kinetic energy will zero

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on solving these equations we get kinetic energy initial

KE_{i} = 5.65\times 10 ^{-12} \times \frac  {1 eV}{1.6 \times 10^{-19}}

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That is, the alpha particle must be fired with 35.33 MeV of kinetic energy. An alpha particle with charge q = 2  e

and gains kinetic energy K  =e∆V  ..........(ii)

 by accelerating through a potential difference ∆V

Thus the alpha particle will

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equating (i) and second equation we get

e∆V  = 35.33 Me V

\Delta V = \frac{35.33}{2}  MV\\\Delta V    = 1.8 \times 10^7 V

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3 years ago
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