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Leno4ka [110]
2 years ago
8

A circular swimming pool has a diameter of 14 m, the sides are 4 m high, and the depth of the water is 3 m. How much work (in Jo

ules) is required to pump all of the water over the side
Physics
1 answer:
vredina [299]2 years ago
7 0

The work required is Wa = 2954112 J

Given:

swimming pool diameter = 14 m

length of sides = 4 m

height of water = 3 m

To Find:

work required to pump water

Solution: The radius of the swimming pool is

r = 14/2 = 7 m

The work is mathematically given as

W = Force x distance

Now force is mathematically given as

F = density x area x height of pool = p*(πr²)dx

Now the work done to pump all of the water over the side

W = ∫p*(πr²)(H-x)dx = ∫1000*9.81*(π*7^2)(4-x)dx

W = 64000*9.8π∫(4-x) dx = 64000*9.8π{4(3) - 3/2}

W = 2954112 J

So, work required is Wa = 2954112 J

Learn more about Work here:

brainly.com/question/8119756

#SPJ4

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The procedure to find the x-velocity is very similar, but instead of using sine, we will use the cosine of theta. Recall that cosΘ=adjacent/hypotenuse. Once again plugging this scenario's numbers into that, you end up with cos60 = vₓ/15. Multiplying this out gives you vₓ = 15cos60. Once again, plug this into your calculator. 7.5 m/s should be your answer. This is the velocity in the x-direction.

By the way, a quick way to find the components of a vector, whether it's velocity, force, or whatever else, is to use these functions. Generally, if the vector points somewhere that's not along an axis, you can use this rule. The x-component of the vector is equal to hypotenuse*cosΘ and the y-component of the vector is equal to hypotenuse*sinΘ.

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