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Leno4ka [110]
2 years ago
8

A circular swimming pool has a diameter of 14 m, the sides are 4 m high, and the depth of the water is 3 m. How much work (in Jo

ules) is required to pump all of the water over the side
Physics
1 answer:
vredina [299]2 years ago
7 0

The work required is Wa = 2954112 J

Given:

swimming pool diameter = 14 m

length of sides = 4 m

height of water = 3 m

To Find:

work required to pump water

Solution: The radius of the swimming pool is

r = 14/2 = 7 m

The work is mathematically given as

W = Force x distance

Now force is mathematically given as

F = density x area x height of pool = p*(πr²)dx

Now the work done to pump all of the water over the side

W = ∫p*(πr²)(H-x)dx = ∫1000*9.81*(π*7^2)(4-x)dx

W = 64000*9.8π∫(4-x) dx = 64000*9.8π{4(3) - 3/2}

W = 2954112 J

So, work required is Wa = 2954112 J

Learn more about Work here:

brainly.com/question/8119756

#SPJ4

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artcher [175]

The temperature at which the sample of liquid turns to gas at 135 °C is termed as boiling point.

Answer: Option A

<u>Explanation: </u>

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In this case, the liquid on heating gets converted to gaseous state after attaining a particular temperature say 135 °C. So, this process of conversion from liquid to gaseous state on heating is termed as boiling.

The temperature at which a liquid converts to gas is termed as the boiling point of that liquid.

3 0
3 years ago
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In a mass spectrometer a particle of mass m and charge q is accelerated through a potential difference V and allowed to enter a
Ghella [55]

Answer:

m = B²qR² / 2 V

Explanation:

If v be the velocity after acceleration under potential difference of V

kinetic energy  = loss of electric potential energy

1/2 m v² = Vq ,

v² = 2 Vq / m ----------------------- ( 1 )

In magnetic field , charged particle comes in circular motion in which magnetic force provides centripetal force

magnetic force = centripetal force

Bqv = mv² / R

v = BqR / m

v² = B²q²R² / m²  ------------------------- (2)

from (1) and (2)

B²q²R² / m²  = 2 Vq / m

m = B²q²R² / 2 Vq

m = B²qR² / 2 V

7 0
3 years ago
Starting at t = 0 s , a horizontal net force F⃗ =( 0.285 N/s )ti^+(-0.460 N/s2 )t2j^ is applied to a box that has an initial mom
Irina-Kira [14]

Answer:

Explanation:

We know that Impulse = force x time

impulse = change in momentum

change in momentum = force x time

Force F = .285 t -.46t²

Since force is variable

change in momentum = ∫ F dt  where F is force

= ∫ .285ti - .46t²j dt

= .285 t² / 2i - .46 t³ / 3 j

When t = 1.9

change in momentum = .285 x 1.9² /2 i  -  .46 x 1.9³ / 3 j

= .514i - 1.05 j

final momentum

= - 3.1 i + 3.9j +.514i - 1.05j

= - 2.586 i + 2.85j

x component = - 2.586

y component = 2.85

7 0
3 years ago
In any problems involving circular motion, which way does the tangential speed vector point?
Anton [14]

In what may be one of the most remarkable coincidences in
all of physical science, the tangential component of circular
motion points along the tangent to the circle at every point. 

The object on a circular path is moving in that exact direction
at the instant when it is located at that point in the circle.  The
centripetal force ... pointing toward the center of the circle ...
is the force that bends the path of the object away from a straight
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3 years ago
A baseball travels 200 metes in 6 seconds, what is the baseball’s velocity?
goldenfox [79]

Answer:

33.33 m/sec

Explanation:

A baseball travels 200 metes in 6 seconds,

what is the baseball’s velocity?

use the formula: velocity = distance over time

where (d) distance = 200 m

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plugin values into the formula:

v = d / t

  = 200 m / 6 sec

  = 33.33 m/sec.

therefore, the baseball's velocity is 33.33 m/sec

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