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3 years ago

The isotope sulfur is represented as sulfur-35 or S-35, what does the number 35 signify?

1 answer:

3 0

It would be S - 35 because people made the short form of each element to make it easier to understand and it is also used all around the world and 35 is the atomic number. Hope this helps ;)

You might be interested in

which Law relates temperature,pressure,volume,and the number of miles of a gas under perfect conditions

spin [16.1K]

Answer:

the ideal gas law

Explanation:

hope this helps

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3 0

3 years ago

A sample of argon has a volume of 1.2 L at STP. If the temperature is increased to 21 c and the pressure is lowered to 0.80 atm,

Nuetrik [128]

Answer:

The new volume is 1.62 L

Explanation:

Boyle's law says:

"The volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure." It is expressed mathematically as:

Pressure * Volume = constant

o P * V = k

Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

$\frac{V}{T}=k$

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature is decreased, the gas pressure decreases. So this law indicates that the quotient between pressure and temperature is constant.

Gay-Lussac's law can be expressed mathematically as follows:

$\frac{P}{T}=k$

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law.

$\frac{P*V}{T}=k$

Having an initial state 1 and a final state 2 it is possible to say that:

$\frac{P1*V1}{T1} =\frac{P2*V2}{T2}$

Standard temperature and pressure (STP) indicate pressure conditions P = 1 atm and temperature T = 0 ° C = 273 ° K. Then:

P1= 1 atm
V1= 1.2 L
T1= 273 °K
P2= 0.80 atm
V2= ?
T2= 21°C= 294 °K

Replacing:

$\frac{1 atm* 1.2 L}{273K} =\frac{0.8 atm*V2}{294K}$

Solving:

$V2=\frac{1 atm*1.2 L}{273 K} *\frac{294 K}{0.8 atm}$

V2= 1.62 L

The new volume is 1.62 L

8 0

2 years ago

The rate of effusion of an unknown gas was measured and found to be 11.9 mL/min. Under identical conditions, the rate of effusio

iren2701 [21]

Answer : The correct option is, (B) $CO_2$

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

$R\propto \sqrt{\frac{1}{M}}$

or,

$(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}$ ..........(1)

where,

$R_1$ = rate of effusion of unknown gas = $11.9\text{ mL }min^{-1}$

$R_2$ = rate of effusion of oxygen gas = $14.0\text{ mL }min^{-1}$

$M_1$ = molar mass of unknown gas = ?

$M_2$ = molar mass of oxygen gas = 32 g/mole

Now put all the given values in the above formula 1, we get:

$(\frac{11.9\text{ mL }min^{-1}}{14.0\text{ mL }min^{-1}})=\sqrt{\frac{32g/mole}{M_1}}$

$M_1=44.2g/mole$

The unknown gas could be carbon dioxide $(CO_2)$ that has approximately 44 g/mole of molar mass.

Thus, the unknown gas could be carbon dioxide $(CO_2)$

5 0

3 years ago

If the density of a 45.0 cm3 block of wood is 0.65 g/ml what is the mass of the wood?

wlad13 [49]

Answer:

$\boxed {\tt mass=29.25 \ grams}$

Explanation:

The density formula is mass over volume.

$d=\frac{m}{v}$

Rearrange the formula for the mass, m. Multiply both sides of the formula by v.

$d*v=\frac{m}{v}*v$

$d*v=m$

Mass can be found by multiplying the density and volume. The density is 0.65 grams per milliliter and the volume is 45.0 cubic centimeters.

A cubic centimeter is equal to a milliliter.

Therefore, 45 cubic centimeters also equals 45 milliliters.

$d= 0.65 \ g/mL\\v= 45 \ mL$

Substitute the values into the formula.

$0.65 \ g/mL * 45 \ mL=m$

Multiply. Note the milliliters, or mL will cancel out.

$0.65 \ g * 45=m$

$29.25 \ g=m$

The mass of the wood is 29.25 grams.

5 0

3 years ago

How many moles in one gram of Calcium ??

kirill [66]

Answer:

0.0249 moles in 1 g of Ca

Explanation:

Let's think in the molar mass of Ca.

Ca = 40.08 g/mol

So 1 mol weighs 40.08 grams, or in the opposite 40.08 grams is the weigh of 1 mol

The rule of three will be:

40.08 g are contained in 1 mol

1 g may be contained in (1 . 1) / 40.08 = 0.0249 moles

8 0

3 years ago