1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
scoundrel [369]
3 years ago
10

Who invented carbon element?

Chemistry
1 answer:
igor_vitrenko [27]3 years ago
8 0
Carbon discovered in Prehistoric times.. Discoverer will probably never be known
You might be interested in
Pleasee help <br> will name brainliest
zmey [24]

Answer:

0.125. work- divide the volume value by 1000

873. work- multiply the length value by 100

98100. work- Conversion factor: 1 kg = 100000 cg

1) Centigram = Kilogram * 100000

2) Centigram = 0.981 * 100000

3) Centigram = 98100

285.65. work- 12.5°C + 273.15 = 285.65K

446.85. work- 720K − 273.15 = 446.85°C

346.25. work- 73.1°C + 273.15 = 346.25K

Explanation:

i hope this helps:)  brainliest plss??

8 0
3 years ago
How can you use knowledge of a minerals chemical makeup or use?
mel-nik [20]

and D. to identify minerals

8 0
3 years ago
Read 2 more answers
What is a property of a substance?
S_A_V [24]

Answer:

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance.

Explanation:

Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change.

8 0
2 years ago
He rate constant of a reaction is 4.55 × 10−5 l/mol·s at 195°c and 8.75 × 10−3 l/mol·s at 258°c. what is the activation energy o
Xelga [282]

Answer : The activation energy of the reaction is, 17.285\times 10^4kJ/mole

Solution :  

The relation between the rate constant the activation energy is,  

\log \frac{K_2}{K_1}=\frac{Ea}{2.303\times R}\times [\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = initial rate constant = 4.55\times 10^{-5}L/mole\text{ s}

K_2 = final rate constant = 8.75\times 10^{-3}L/mole\text{ s}

T_1 = initial temperature = 195^oC=273+195=468K

T_2 = final temperature = 258^oC=273+258=531K

R = gas constant = 8.314 kJ/moleK

Ea = activation energy

Now put all the given values in the above formula, we get the activation energy.

\log \frac{8.75\times 10^{-3}L/mole\text{ s}}{4.55\times 10^{-5}L/mole\text{ s}}=\frac{Ea}{2.303\times (8.314kJ/moleK)}\times [\frac{1}{468K}-\frac{1}{531K}]

Ea=17.285\times 10^4kJ/mole

Therefore, the activation energy of the reaction is, 17.285\times 10^4kJ/mole

8 0
3 years ago
Read 2 more answers
What is most likely to happen when two fluorine atoms bond?
alina1380 [7]

Answer:

A nonpolar covalent bond

8 0
3 years ago
Read 2 more answers
Other questions:
  • In what way would readings from a digital thermometer be preferable to those from a liquid-based thermometer?
    9·2 answers
  • Tomato juice has a pH of 4.20. Calculate the [H3O+] and [OH–] in tomato juice.
    7·1 answer
  • How are the noble gases stable and do they exist separatly with no other element
    12·1 answer
  • 14 billion years (roughly the age of the universe) to seconds. (Assume there are 365 days in a year.)
    12·1 answer
  • A lightbulb filled with argon gas has a volume of 75 mL at STP. How many moles of argon gas does the lightbulb contain?
    14·1 answer
  • You probably already know the names of some molecules. Identify which compound (water, salt, carbon dioxide, or methane) corresp
    7·2 answers
  • HELP HELP ME PLSS
    9·1 answer
  • Atomic mass is determined by the number of protons plus the number of _____. a)electrons b)neutrons c)charges d)atoms
    5·2 answers
  • A piece of unknown metal weighs 348g. When the metal piece absorbs 6.64kj of heat , its temperature increases from 24.4C to 43.6
    14·1 answer
  • Why aren’t subatomic particles, which are smaller than an atom, considered to be the building blocks of matter?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!