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andrew-mc [135]
3 years ago
6

A stone is dropped from a tower of height 3600cm.Find the velocity by which it strike the ground.Also,find the time taken to rea

ch the ground.​
Physics
2 answers:
andriy [413]3 years ago
5 0

Answer:

Explanation:

Here h=36m, a=g=10m/s, u=0

Use s=ut+(1/2)at^2

36=0*t+(10t^2)/2

time=2.68 sec

As from the formula of final velovity, v=(2gh)^1/2

v=(2*10*36)^1/2

v=(720)^1/2

v=26.83………This is the final velocity

enyata [817]3 years ago
5 0

Answer:

Explanation:

s = vit + 1/2 gt*2

36 = 0 + 1/2 x 9.8 x t*2

t*2 = 7.34

t = 2.7sec

now,

2gs = vf*2 - vi*2

2 x 9.8 x 36 = vf*2 - 0

vf*2 = 705.6

vf = 26.5m/s

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A tortoise and hare start from rest and have a race. As the race begins, both accelerate forward. The hare accelerates uniformly
Mnenie [13.5K]

Answer:

The acceleration of the hare once it begins to slow down is -0.68 m/s²

The acceleration of the tortoise is 0.28 m/s²

Explanation:

The equations that describe the position and velocity of the hare and the tortoise are the following:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where:

x = position at time t

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

v = velocity at time t

To find the acceleration of the hare once it begins to slow down, we have to find how much time the hare traveled during the deceleration and what was its initial speed.

First, the hare moves with constant acceleration for 4.7 s. Then, its velocity at  t = 4.7 s will be:

v = v0 + a · t    (v0 = 0 because the hare starts form rest)

v = a · t = 0.9 m/s² · 4.7 s = <u>4.2 m/s</u>

<u />

The distance traveled by the hare while accelerating can be calculated using the equation of the position:

x = x0 + v0 · t + 1/2 · a · t²      (x0 = 0 and v0 = 0)

x = 1/2 · a · t² = 1/2 · 0.9 m/s² · (4.7)² = <u>9.9 m</u>

<u />

Then, the hare runs at a constant speed of 4.2 m/s for 11.7 s. The distance traveled at constant speed will be:

x =  v · t

x = 4.2 m/s · 11.7 s = <u>49.1 m</u>

<u />

Then, the distance traveled by the hare while slowing down was:

Distance traveled while slowing down = 72 m - 49.1 m - 9.9 m = 13 m

Let´s find how much time it took the hare to come to stop, so we can calculate the acceleration. We know that when the position is 13 m, the velocity is 0.

v = v0 + a · t

0 = 4.2 m/s + a · t

-4.2 m/s / t = a

Replacing in the equation of the position:

x = v0 · t + 1/2 · a · t²      (considering x0 as the point at which the hare started to slow down)

13 m = 4.2 m/s · t - 1/2 · 4.2 m/s / t · t²

13 m = 4.2 m/s · t - 2.1 m/s · t

13 m = 2.1 m/s · t

t = 13 m / 2.1 m/s

t = 6.2 s

Then, the acceleration of the hare while slowing down will be:

-v0/t = a

-4.2 m/s / 6.2 s = a

a = -0.68 m/s²

The acceleration of the hare once it begins to slow down is -0.68 m/s²

The hare traveled 72 m in (6.2 s + 11.7 s + 4.7 s) 22.6 s. The tortoise reaches the final position of the hare at the same time, so, using the equation of the position we can calculate the acceleration of the tortoise:

x = x0 + v0 · t + 1/2 · a · t²     (x0 = 0 and v0 = 0)

x = 1/2 · a · t²

72 m = 1/2 · a · (22.6 s)²

144 m / (22.6 s)² = a

a = 0.28 m/s²

The acceleration of the tortoise is 0.28 m/s²

6 0
3 years ago
This is 100 points. When i find out how i will put the first person to answer as brainiest.
grin007 [14]

Answer:

Thank you so much! Have a great day!

3 0
3 years ago
DOUBLE POINTS AND BRAINLIEST ANSWER PLEASE THIS IS VERY IMPORTANT FOR UNIT TEST TOMORROW for each of these diagrams in the pictu
Anni [7]
Maybe nobody ever mentioned it to you, but it turns out that
current is another one of those things that's always conserved ...
it can't created or destroyed, just like energy and mass. 

The total current in a circuit is always the same, but it can get
split up and travel through different paths for a while.

<span>==>  The total current is just the amount of current
         that's flowing in
and out of </span><span>the battery.

Diagram #1).
</span>The total current coming out of the battery is 15 A.
That current is going to split up when it reaches the resistors.
   Part of it will flow through each resistor, but both of them
   will still add up to  15 A .
You have  9 A  flowing through one resistor.
So the current in the other resistor is  (15 - 9)  =<span>  6 A.

Diagram #2).
</span>The total current coming out of the battery is 10 A.
That current is going to split up when it reaches the resistors.
   Part of it will flow through each resistor, but all of them
   will still add up to  10 A .
You have  2.5 A  through one resistor and  3.5 A through another one.
So the amount left for the last resistor is  (10 - 2.5 - 3.5)  =<span>  4 A.</span>
8 0
3 years ago
Suppose you are at the center of a large freely-rotating horizontal turntable in a carnival funhouse. As you crawl toward the ed
I am Lyosha [343]

Answer:

c. remains the same, but the RPMs decrease.

Explanation:

Because there aren't external torques on the system composed by the person and the turntable it follows that total angular momentum (I) is conserved, that means the total angular momentum is a constant:

\overrightarrow{L}=constant

The total angular momentum is the sum of the individual angular momenta, in our case we should sum the angular momentum of the turntable and the angular momentum of a point mass respect the center of the turntable (the person)

\overrightarrow{L_{turnatble}}+\overrightarrow{L_{person}}=constant (1)

The angular momentum of the turntable is:

\overrightarrow{L_{turnatble}}=I\overrightarrow{\omega} (2)

with I the moment of inertia and ω the angular velocity.

The angular momentum of the person respects the center of the turntable is:

\overrightarrow{L_{person}}=\overrightarrow{r}\times m\overrightarrow{v} (3)

with r the position of the person respects the center of the turntable, m the mass of the person and v the linear velocity

Using the fact v=\omega r:

\overrightarrow{L_{person}}=\overrightarrow{r}\times rm\overrightarrow{\omega}(3)

By (3) and (2) on (1) and working only the magnitudes (it's all that we need for this problem):

I\omega+r^{2}m\omega=constant

\omega(I+r^{2}m)=constant

Because the equality should be maintained, if we increase the distance between the person and the center of the turntable (r), the angular velocity should decrease to maintain the same constant value because I and m are constants, so the RPM's (unit of angular velocity) are going to decrease.

4 0
4 years ago
________ reaction time involves selecting a specific and correct response from several choices when presented with several diffe
notsponge [240]
The answer would be complex reaction time
4 0
3 years ago
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