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andriy [413]
3 years ago
6

Based on the given angle measures, which triangle has side length measures that could be correct?

Mathematics
2 answers:
Likurg_2 [28]3 years ago
8 0

Answer

The triangle in the figure 4 is correct .

Reason

by using the trignometric identity

tan\theta = \frac{Perpendicular}{Base}

Thus

tan 30^{\circ} = \frac{Perpendicular}{Base}

tan 30 ^{\circ} =\frac{1}{\sqrt{3}}

Now in the figure (1)

tan 30^{\circ} = \frac{13.9}{8}

\frac{1}{\sqrt{3}} = \frac{13.9}{8}

on simplify

0.5774 \neq 1.7375

thus side length measures in the figure (1) is not correct .

Now in the figure (2)

tan30^{\circ} =\frac{16}{8} \\ \frac{1}{\sqrt{3}} =\frac{16}{8} \\ 0.577 \neq 2

thus side length measures in the figure (2) is not correct .

Now in the figure (3)

tan 30 ^{\circ} = \frac{8}{16} \\ \frac{1}{\sqrt{3}} =\frac{8}{16} \\ 0.577\neq0.5

thus side length measures in the figure (3) is not correct .

Now in the figure (4)

tan30^{\circ} = \frac{8}{13.9} \\ \frac{1}{\sqrt{3}} =\frac{8}{13.9}\\ 0.577 = 0.576(approx)

 Therefore the figure (4) is correct triangle has side length measures that could be correct

Hence proved


 


Phoenix [80]3 years ago
8 0

Answer:

The answer is D on edgen.

Step-by-step explanation:

D. the 4th figure

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Step-by-step explanation:

<u><em>The correct question is</em></u>

Suppose that ∅ Is an angle with csc(∅)=-12/5 and ∅ Is not in the third quadrant. Compute the exact value of Tan(∅).

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∅ Is not in the third quadrant ----> given problem

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That means ----> ∅ Is in the fourth quadrant

step 1

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we have

csc(\theta)=-\frac{12}{5}

we know that

csc(\theta)=\frac{1}{sin(\theta)}

therefore

sin(\theta)=-\frac{5}{12}

step 2

Find the value of cos(\theta)

we know that

sin^2(\theta)+cos^2(\theta)=1

we have

sin(\theta)=-\frac{5}{12}

substitute

(-\frac{5}{12})^2+cos^2(\theta)=1

\frac{25}{144}+cos^2(\theta)=1

cos^2(\theta)=1-\frac{25}{144}

cos^2(\theta)=\frac{119}{144}

cos(\theta)=\frac{\sqrt{119}}{12} ---> is positive (IV Quadrant)

step 3

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we know that

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

substitute the values

tan(\theta)=-\frac{5}{12} : \frac{\sqrt{119}}{12}=-\frac{5}{\sqrt{119}}

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Answer:

Option C is the correct option.

In other words, the quadratic regression y=32.86\:\left(x\right)^2-379.14\left(x\right)+1369.14\: best fits the data set, as it gets very much close to the data values given in the data table.

The graph of the equation  y=32.86\:\left(x\right)^2-379.14\left(x\right)+1369.14\:  is also attached.

Step-by-step explanation:

x                 y

3                470

4                416

5                403

Analyzing Option A:

Considering the equation

y=32.86\:\left(x\right)^2+379.14\left(x\right)-1369.14\:

From (3, 470), putting x = 3

y=32.86\:\left(3\right)^2+379.14\left(3\right)-1369.14\:

y=64.02

From (4, 470), putting x = 4

y=32.86\:\left(4\right)^2+379.14\left(4\right)-1369.14\:\:

y=673.18

From (5, 403), putting x = 5

y=32.86\:\left(5\right)^2+379.14\left(5\right)-1369.14\:

y=1348.06

Analyzing Option B:

y=32.86\:\left(x\right)^2-379.14\left(x\right)

From (3, 470), putting x = 3

y=32.86\:\left(3\right)^2-379.14\left(3\right)

y=-841.68

From (4, 470), putting x = 4

y=32.86\:\left(4\right)^2-379.14\left(4\right)

\:y=-990.8

From (5, 403), putting x = 5

y=32.86\:\left(5\right)^2-379.14\left(5\right)

\:y=-1074.2

Analyzing Option C:

Considering the equation

y=32.86\:\left(x\right)^2-379.14\left(x\right)+1369.14\:

From (3, 470), putting x = 3

y=32.86\:\left(3\right)^2-379.14\left(3\right)+1369.14\:

y=527.46

So, the approximately result is (3, 527)

From (4, 470), putting x = 4

y=32.86\:\left(4\right)^2-379.14\left(4\right)+1369.14\:

y=378.34

So, the approximately result is (4, 378)

From (5, 403), putting x = 5

y=32.86\:\left(5\right)^2-379.14\left(5\right)+1369.14\:\:\:

y=294.94

So, the approximately result is (5, 295)

Analyzing Option D:

Considering the equation

y=-1369.14\:\left(x\right)^2-379.14\left(x\right)+32.86

From (3, 470), putting x = 3

y=-1369.14\:\left(3\right)^2-379.14\left(3\right)+32.86\:\:

y=-13426.82

From (4, 470), putting x = 4

y=-1369.14\:\left(4\right)^2-379.14\left(4\right)+32.86

y=-23389.94

From (5, 403), putting x = 5

y=-1369.14\:\left(5\right)^2-379.14\left(5\right)+32.86\:\:

y=-36091.34

Therefore, from the above calculations and analysis, we conclude that Option C is the correct option.

In other words, the quadratic regression y=32.86\:\left(x\right)^2-379.14\left(x\right)+1369.14\: best fits the data set, as it gets very much close to the data values given in the data table.

The graph of the equation  y=32.86\:\left(x\right)^2-379.14\left(x\right)+1369.14\:  is also attached.

3 0
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