Please help with c d and e

Identify the equation in slope-intercept form for the line with the given slope that contains the given point. Slope =2; (1,4)

Elina [12.6K]

Slope-intercept form: y=mx+b, with m being the slope and b being the y-intercept. First, plug in the given slope into the slope form:

y=2x+b

Now, given the coordinates (1,4), you can plug the coordinates into the equation for x and y respectively, to solve for b (the y-intercept).

4=2(1)+b

4=2+b

Subtract 2 from both sides.

2=b

The y-intercept is 2.

Now, plug that into the equation:

y=2x+2

The answer is y=2x+2.

I hope this helps :)

3 0

3 years ago

If a total amount is 5 7/8 and 6 people need to be fed, how much is a serving size?

PolarNik [594]

Answer:

47/48

Explanation:

Since 5 7/8 is so close to 6, it is easier to work this problem by considering the difference.

The serving size is 1/6 of the total amount, so you want to find ...

... (5 7/8) × (1/6)

Following the observation above, we can compute it as ...

... (6 - 1/8) × (1/6) = (6/6) - (1/8)×(1/6)

... = 1 - 1/48

... = 47/48

5 0

3 years ago

What is the value of x, y, and z?

baherus [9]

The value of x,y, and z 85+ 84 right?

3 0

2 years ago

Multiply (7x – 6)(8x +3). A. 56x2 – 27x – 18 B. 12x2 – 50x + 8 C. 56x2 – 18 D. 56x2 – 69x + 18

Paha777 [63]

You can use the FOIL method to solve: multiply FIRST, multiply OUTSIDE, multiply INSIDE, multiply LAST to help remember to multiply all terms.

=(7x – 6)(8x + 3)
multiply first term by first term, multiply outside by outside, inside by inside, last by last
=(7x*8x) + (7x*3) + (-6*8x) + (-6*3)
multiply terms
=56x^2 + 21x - 48x - 18
combine like terms
=56x^2 - 27x - 18

ANSWER: A) 56x^2 - 27x - 18

Hope this helps! :)

7 0

3 years ago

A survey of 27 randomly sampled judges employed by the state of Florida found that they earned an average wage (including benefi

Afina-wow [57]

Answer:

a) sample mean $x^{bar}$ = 63

b) 95% confidence interval for the population mean wage (including benefits) for these employees is ( 60.58, 65.42 )

c) sample size is 26

Step-by-step explanation:

given the data in the question

a) estimate of the population mean

sample mean $x^{bar}$ = ($63.00 per hour) = 63

b)

given that; standard deviation σ = 6.11, sample size n = 27

df = n-1 = 27 - 1 = 26

now at 95% CI, t will be;

∝ = 1 - 95% = 0.05, $t_{∝/2}$ = 0.05/2 = 0.025

$t_{∝/2, df}$ = $t_{0.025, 26}$ = 2.056

Margin of Error E = $t_{∝/2, df}$ × (σ/√n)

Margin of Error E = 2.056 × (6.11/√27)

Margin of Error E = 2.056 × 1.17587

Margin of Error E = 2.4175 ≈ 2.42

CI estimate of the population mean will be; ( 95% )

$x^{bar}$ - E < μ < $x^{bar}$ + E

we substitute

63 - 2.42 < μ < 63 + 2.42

60.58 < μ < 65.42

Therefore, 95% confidence interval for the population mean wage (including benefits) for these employees is ( 60.58, 65.42 )

c)

At 90% confidence level and Margin of Error of 2

sample size n = ?

∝ = 1-90% = 0.10, ∝/2 = 0.10/2 = 0.05

$Z_{∝/2}$ = $Z_{0.05}$ = 1.645

Sample size n = ( $Z_{∝/2}$ × σ/ / E )²

we substitute

Sample size n = (1.645×6.11 / 2)²

n = (10.05095 / 2)²

n = ( 5.025475)²

n = 25.255

number of employed judges cant be decimal,

Therefore, sample size is 26

8 0

3 years ago