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stealth61 [152]
2 years ago
13

A student is running a 5-kilometer race. He runs 1 kilometer every 3 minutes. Select the function that describes his distance fr

om the finish line after x minutes. (1 point) A.f(x) = − 1 over 3 x + 5 B.f(x) = − 1 over 5 x + 3 C.f(x) = 1 over 5 x + 5 D. f(x) = 1 over 3 x + 3
Mathematics
1 answer:
ICE Princess25 [194]2 years ago
3 0
The function that describes his distance from the finish line is f(x) = - 1/3 x + 5 the correct answer between all the choices gives is the first choice or letter A
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What is 1/2 divided by 6?
jok3333 [9.3K]

Answer:

1/12 or 0.0833

Step-by-step explanation:

1/2 divided by 6

1/2x6

1/12!

7 0
3 years ago
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McDonalds sells a 20-piece chicken nugget for $5.20. What is the cost per nugget?
jonny [76]

Answer:

O.26

Step-by-step explanation:

Divide The cost from the pieces

4 0
3 years ago
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Find the coordinates of the points of intersection of the graphs with coordinate axes: y=− 1/4 x+2
bearhunter [10]

Answer:


Step-by-step explanation:

Here, you can use a simple formula.

To find the point of intersection you just put x=0 or y=0.

Because, if a graph intersects x-axis, then at this point  y=0

Similarly, if a graph intersects y-axis, then at this point  x=0


So, for our given line.

y=-1/4 x +2

when , x=0 , y=-1/4 (0)+2=2

So, the graph intersects y-axis at   y=2


when , y=0 ,

then    0=-1/4 x+2

       or, 1/4 x=2

       or, x=8    [multiplying by  4]

So, the graph intersects x-axis at   x=8

3 0
3 years ago
At 8:00 a.m., there were t inches of snow on the ground. At 5:00 p.m., there were 3t inches of snow on the ground. How many more
Anastaziya [24]

we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.

<h3>How many more inches of snow were on the ground at 5:00 p.m. than at 8:00 a.m.?</h3>

We know that at 8:00 a.m. there were t inches of snow in the ground.

At 5:00 p.m. there were 3t inches of snow in the ground.

Then the difference between the heights of the snow is:

3t- t = 2t

And we know that at 5:00 p.m. there were 12 inches of snow then we can solve the linear equation for t:

3t = 12in

t = (12in)/3 = 4 in

Replacing that in the difference of heights:

2t = 2*4in = 8in

From this, we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

3 0
2 years ago
The half-life of Radium-226 is 1590 years. If a sample contains 200 mg, how many mg will remain after 1000 years?
adell [148]

Answer: 129.33 g

Step-by-step explanation:

$$Let $p=A \cdot e^{n t}$ \\$(p=$ present amount, $A=$ initial amount, $n=$ decay rate, $t=$ time)

\begin{aligned}&\Rightarrow \text { Given } p=\frac{A}{2} \ a t  \ t=1590 \\&\Rightarrow \frac{1}{2}=e^{1590n} \Rightarrow n=\frac{\ln (1 / 2)}{1590}=-0.00043594162\end{aligned}

$$If $A=200 \mathrm{mg}$ and $t=1000$ then,$$\begin{aligned}P &=200 e^{\left(\frac{\ln \left(1/2\right)}{1590}\right) \cdot 1000} \text \\\\&=129.33 \text { grams}\end{aligned}$$

3 0
2 years ago
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