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3 years ago

Give a rule of the piecewise-defined function. Give the domain and the range.

Mathematics

1 answer:

dimulka [17.4K]3 years ago

3 0

Answer:

Hello your question is incomplete below is the complete question

option B is correct

f(x) = 1 if x ≤ 0

-2 if x > 0

Step-by-step explanation:

The Rule of the piece-wise-defined function is :

from the given figure attached it can be seen that as : x ≤ 0 , y = 1

while for x > 0 , y = -2

therefore option B is correct

f(x) = 1 if x ≤ 0

-2 if x > 0

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For 9 and 9A, find the slope of the line

djverab [1.8K]

For this case we have that by definition, the slope of a line is given by:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}$

Where:

$(x_ {1}, y_ {1})$ and $(x_ {2}, y_ {2})$ are two points through which the line passes.

Question 1:

According to the image, we have the following points:

$(x_ {1}, y_ {1}) :( 2, -6)\\(x_ {2}, y_ {2}): (- 6,5)$

Substituting we have:

$m = \frac {5 - (- 6)} {- 6-2} = \frac {5 + 6} {- 8} = \frac {11} {- 8} = - \frac {11} {8}$

Thus, the slope is: $- \frac {11} {8}$

Question 2:

According to the image, the line goes through the following points:

$(x_ {1}, y_ {1}): (- 1,2)\\(x_ {2}, y_ {2}) :( 2, -2)$

Substituting we have:

$m = \frac {-2-2} {2 - (- 1)} = \frac {-4} {2 + 1} = \frac {-4} {3} = - \frac {4} {3}$

Thus, the slope is: $- \frac {4} {3}$

Answer:

Slope 1: $- \frac {11} {8}$

Slope 2: $- \frac {4} {3}$

3 0

3 years ago

A veterinarian collects data on the number of times race horses are raced during their careers. The veterinarian finds that the

SpyIntel [72]

Answer:

c. (12.12, 18.48)

Step-by-step explanation:

Hello!

The study variable is X: number of times a racehorse is raced during its career.

The average number is X[bar]= 15.3 and the standard deviation is S= 6.8 obtained from a sample of n=20 horses.

To estimate the population mean you need that the variable has a normal distribution, in this case, we have no information about its distribution so I'll assume that it has a normal distribution. With n=20 the most accurate statistic to use for the estimation is a Students-t for one sample, the formula for the interval is:

X[bar] ± $t_{n-1;1-\alpha /2} * \frac{S}{\sqrt{20} }$

$t_{n-1;1-\alpha /2} = t_{19;0.975}= 2.093$

[15.3 ± 2.093 * $\frac{6.8}{\sqrt{20} }$ ]

[12.12; 18.48]

Using a significance level of 95% you'd expect that the true average of times racehorses are raced during their career is included in the interval [12.12; 18.48].

I hope it helps!

8 0

3 years ago

i don't understand how to make it into a graphing form? how do you find the center and radius? (I'm confused because it has a 4x

Vilka [71]

Answer: $\bold{(x-2)^2+(y-3)^2=\dfrac{1}{4}}$