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julia-pushkina [17]
3 years ago
7

Help!!! I need it today Thank you in advance

Physics
1 answer:
svlad2 [7]3 years ago
5 0

Answer:

 F = - k (x-xo) a graph of the weight or applied force against the elongation obtaining a line already proves Hooke's law.

Explanation:

The student wants to prove hooke's law which has the form

          F = - k (x-xo)

To do this we hang the spring in a vertical position and mark the equilibrium position on a tape measure, to simplify the calculations we can make this point zero by placing our reference system in this position.

Now for a series of known masses let's get them one by one and measure the spring elongation, building a table of weight vs elongation,

we must be careful when hanging the weights so as not to create oscillations in the spring

we look for the mass of each weight

         W = mg

          m = W / g

and we write them in a new column, we make a graph of the weight or applied force against the elongation and it should give a straight line; the slope of this line is sought, which is the spring constant.

The fact of obtaining a line already proves Hooke's law.

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A spherically mirrored ball is slowly lowered at New Years Eve as midnight approaches. The ball has a diameter of 8.0 ft. Assume
Archy [21]

Answer:

The distance between mirror and you is 2 ft.

Explanation:

diameter, d = 8 ft

radius of curvature, R = 4 ft

magnification, m = 0.5

focal length, f = R/2 = 4/2 = 2 ft

let the distance of object is u and the distance of image is v.

\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\\\\\frac{1}{2}=\frac{1}{v}+\frac{1}{u}\\\\v = \frac {2 u}{u - 2}

Use the formula of magnification

m = \frac{v}{u}\\\\0.5 =\frac { u}{u - 2}\\ \\u - 2 = 2 u \\\\u = -2 ft

4 0
3 years ago
We have a long wire with a circular cross section and radius a = 2.40 cm. The current density in this wire is uniform, with a to
Alika [10]

Answer:

The magnitude of the magnetic field is 7.49x10⁻⁶T

Explanation:

The magnetic field is:

B=(\frac{\mu i}{2\pi R^{2} } )r

Where

i = current = 3 A

R = radius = 2.4 cm = 0.024 m

r = distance = 0.72 cm = 7.2x10⁻³m

Replacing:

B=(\frac{4\pi x10^{-7} *3}{2\pi *0.024^{2} } )*7.2x10^{-3}= 7.49x10^{-6} T

7 0
3 years ago
for an object that is speeding up in the positive direction what does the displacement vs. time graph look like
avanturin [10]

For an object that is speeding up in the positive direction, its positive displacement is greater every second, and the AMOUNT greater every second is greater than the AMOUNT greater was in the previous second.

So the graph of displacement vs. time is rising as time goes on, and the rise is becoming steeper as time goes on.

The graph is <em>curving upward</em> as time goes on.

3 0
3 years ago
HELP ASAP!!! PLEASE!!!! A driver traveling on the highway at 100km/hr notices the speed limit changes to 50km/hr as a speed came
Talja [164]

Answer:

90m

Explanation:

Speed * time

100*0.9=90m

hope this helped xx

8 0
4 years ago
Andrea and Chuck are riding on a merry-go-round. Andrea rides on a horse at the outer rim of the circular platform, twice as far
velikii [3]

Answer: a) Twice Chuck's

Explanation:

If the angular speed is constant, as the merry - go -round is a rigid body, so the distance between two points must remain the same, it is needed that the points farther the center, move faster than the ones closer to it.

There exists a relationship between tangential and angular speed, as follows, that relates the definitions of linear and angular speed, and the angle definition:

angle = arc / radius ⇒ Δθ/Δt = Δs/Δt / r ⇒ ω = v/r ⇒ v = ω. r

If ω is constant, v is directly proportional to r, distance to the center (radius in a circular platform), so if r is twice for Andrea, her tangential speed must be twice Chuck's.

5 0
4 years ago
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