Calcium oxide CaO = 40+16 = 56
Calcium hydroxide Ca(OH)_2 = 40+16+16+1+1 = 74
The ratio 56:74 is equal to 14:x with x being the unknown mass.
56/14 = 4
74/4 = 18.5
So the answer is 18.5g assuming the water is in excess
Less compassionate around the chocolate
Answer:
B) System.
Explanation:
It is a group of parts working together. They work together to make a whole, therefore they are all a system when working together.
Answer:
K = 0.0003 s⁻¹
Explanation:
The reaction is
2N₂O₅ = 4NO₂ + O₂
The equilibrium is
![K[N_{2} O_{5} ]=-\frac{1}{2} \frac{d[N_{2} O_{5} ]}{dt} \\\int\limits^y_x {d[N_{2} O_{5} ]}{} \, =-2k\int\limits^t_0 {dt} \,\\ln[N_{2} O_{5} ]=-2kt+ln[N_{2} O_{5} ]](https://tex.z-dn.net/?f=K%5BN_%7B2%7D%20O_%7B5%7D%20%5D%3D-%5Cfrac%7B1%7D%7B2%7D%20%5Cfrac%7Bd%5BN_%7B2%7D%20O_%7B5%7D%20%5D%7D%7Bdt%7D%20%5C%5C%5Cint%5Climits%5Ey_x%20%7Bd%5BN_%7B2%7D%20O_%7B5%7D%20%5D%7D%7B%7D%20%5C%2C%20%3D-2k%5Cint%5Climits%5Et_0%20%7Bdt%7D%20%5C%2C%5C%5Cln%5BN_%7B2%7D%20O_%7B5%7D%20%5D%3D-2kt%2Bln%5BN_%7B2%7D%20O_%7B5%7D%20%5D)
a plot is attached
From the plot, the slope is -0.0006
-2 * K = -0.0006
K = 0.0003 s⁻¹
The molarity of the hydrochloric acid, HCl solution given the data is 0.079 M
<h3>Balanced equation </h3>
HCl + NaOH —> NaCl + H₂O
From the balanced equation above,
- The mole ratio of the acid, HCl (nA) = 1
- The mole ratio of the base, NaOH (nB) = 1
<h3>How to determine the molarity of HCl </h3>
- Molarity of base, NaOH (Mb) = 0.137 M
- Volume of base, NaOH (Vb) = 16.1 mL
- Volume of acid, HCl (Va) = 27.9 mL
- Molarity of acid, HCl (Ma) =?
MaVa / MbVb = nA / nB
(Ma × 27.9) / (0.137 × 16.1) = 1
(Ma × 27.9) / 2.2057 = 1
Cross multiply
Ma × 27.9 = 2.2057
Divide both side by 27.9
Ma = 2.2057 / 27.9
Ma = 0.079 M
Thus, the molarity of the HCl solution is 0.079 M
Learn more about titration:
brainly.com/question/14356286
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