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sdas [7]
3 years ago
6

The following data are obtained for the decomposition of N2O5 at a certain temperature: 2N2O5(g) ↔ 4NO2(g) + O2(g) Time(s) 0 200

400 600 800 N2O5 (atm) 2.70 2.41 2.15 1.92 1.71 Find the rate constant kobs for this first-order decomposition reaction. (Enter in sec-1)
Chemistry
1 answer:
cricket20 [7]3 years ago
6 0

Answer:

K = 0.0003 s⁻¹

Explanation:

The reaction is

2N₂O₅ = 4NO₂ + O₂

The equilibrium is

K[N_{2} O_{5} ]=-\frac{1}{2} \frac{d[N_{2} O_{5} ]}{dt} \\\int\limits^y_x {d[N_{2} O_{5} ]}{} \, =-2k\int\limits^t_0 {dt} \,\\ln[N_{2} O_{5} ]=-2kt+ln[N_{2} O_{5} ]

a plot is attached

From the plot, the slope is -0.0006

-2 * K = -0.0006

K = 0.0003 s⁻¹

Download xlsx
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