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Flura [38]
2 years ago
9

An aqueous solution of hydrochloric acid is standardized by titration with a 0.137 M solution of sodium hydroxide. If 16.1 mL of

base are required to neutralize 27.9 mL of the acid, what is the molarity of the hydrochloric acid solution
Chemistry
1 answer:
Andre45 [30]2 years ago
5 0

The molarity of the hydrochloric acid, HCl solution given the data is 0.079 M

<h3>Balanced equation </h3>

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

  • The mole ratio of the acid, HCl (nA) = 1
  • The mole ratio of the base, NaOH (nB) = 1

<h3>How to determine the molarity of HCl </h3>
  • Molarity of base, NaOH (Mb) = 0.137 M
  • Volume of base, NaOH (Vb) = 16.1 mL
  • Volume of acid, HCl (Va) = 27.9 mL
  • Molarity of acid, HCl (Ma) =?

MaVa / MbVb = nA / nB

(Ma × 27.9) / (0.137 × 16.1) = 1

(Ma × 27.9) / 2.2057  = 1

Cross multiply

Ma × 27.9 = 2.2057

Divide both side by 27.9

Ma = 2.2057 / 27.9

Ma = 0.079 M

Thus, the molarity of the HCl solution is 0.079 M

Learn more about titration:

brainly.com/question/14356286

#SPJ1

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A balanced equation for the reaction will go a great deal in obtaining our desired result. So, let us write a balanced equation for the reaction

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