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Flura [38]
2 years ago
9

An aqueous solution of hydrochloric acid is standardized by titration with a 0.137 M solution of sodium hydroxide. If 16.1 mL of

base are required to neutralize 27.9 mL of the acid, what is the molarity of the hydrochloric acid solution
Chemistry
1 answer:
Andre45 [30]2 years ago
5 0

The molarity of the hydrochloric acid, HCl solution given the data is 0.079 M

<h3>Balanced equation </h3>

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

  • The mole ratio of the acid, HCl (nA) = 1
  • The mole ratio of the base, NaOH (nB) = 1

<h3>How to determine the molarity of HCl </h3>
  • Molarity of base, NaOH (Mb) = 0.137 M
  • Volume of base, NaOH (Vb) = 16.1 mL
  • Volume of acid, HCl (Va) = 27.9 mL
  • Molarity of acid, HCl (Ma) =?

MaVa / MbVb = nA / nB

(Ma × 27.9) / (0.137 × 16.1) = 1

(Ma × 27.9) / 2.2057  = 1

Cross multiply

Ma × 27.9 = 2.2057

Divide both side by 27.9

Ma = 2.2057 / 27.9

Ma = 0.079 M

Thus, the molarity of the HCl solution is 0.079 M

Learn more about titration:

brainly.com/question/14356286

#SPJ1

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  • No of moles=2mol=n
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\\ \tt\hookrightarrow PV=nRT

\\ \tt\hookrightarrow V=\dfrac{nRT}{P}

\\ \tt\hookrightarrow V=\dfrac{2(8.314)(300)}{2}

\\ \tt\hookrightarrow V=8.314(300)

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Explanation:

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Elenna [48]

Answer:

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explanation

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4 0
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How many Liters of 0.50M HCl are needed to neutralize 0.050L of 0.101M Ba(OH)2?
Aleksandr-060686 [28]

Answer:

V_{HCl}=5.05x10^{-3}L

Explanation:

Hello,

In this case, since hydrochloric acid and barium hydroxide are in a 2:1 molar ratio, for the neutralization, the following moles equality must be obeyed:

2*n_{HCl}=n_{Ba(OH)_2}

In such a way, in terms of molarities and volumes, we can compute the required volume of hydrochloric acid as shown below:

2*M_{HCl}V_{HCl}=M_{Ba(OH)_2}V_{Ba(OH)_2}\\\\V_{HCl}=\frac{M_{Ba(OH)_2}V_{Ba(OH)_2}}{2M_{HCl}} =\frac{0.101M*0.050L}{2*0.50M} \\\\V_{HCl}=5.05x10^{-3}L

Besr regards.

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Remember, oxygen doesn't burn. Precisely flammable substances obtain substances that burn. Oxygen remains an oxidizing agent, which means it supports the combustion process. Oxygen causes other objects to catch fire at low temperatures and burns hotter and faster. But oxygen itself does not burn. Consequently, if you at present deliver fuel and fire, adding oxygen will provide the fire.

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