Answer:
H = 1/2 g t^2 where t is time to fall a height H
H = 1/8 g T^2 where T is total time in air (2 t = T)
R = V T cos θ horizontal range
3/4 g T^2 = V T cos θ 6 H = R given in problem
cos θ = 3 g T / (4 V) (I)
Now t = V sin θ / g time for projectile to fall from max height
T = 2 V sin θ / g
T / V = 2 sin θ / g
cos θ = 3 g / 4 (T / V) from (I)
cos θ = 3 g / 4 * 2 sin V / g = 6 / 4 sin θ
tan θ = 2/3
θ = 33.7 deg
As a check- let V = 100 m/s
Vx = 100 cos 33.7 = 83,2
Vy = 100 sin 33,7 = 55.5
T = 2 * 55.5 / 9.8 = 11.3 sec
H = 1/2 * 9.8 * (11.3 / 2)^2 = 156
R = 83.2 * 11.3 = 932
R / H = 932 / 156 = 5.97 6 within rounding
Answer:
Explanation:
Heat capacity = mass x specific heat
heat capacity ∝ mass
∝ volume
heat capacity ∝ volume
H₁ / H₂ = V₁ / V₂
H₁ and H₂ are heat capacity corresponding to volume V₁ and V₂.
312 / 100000 = 1 / V₂
V₂ = 100000 / 312
= 320.51 cubic foot.
Answer:
This question appear incomplete
Explanation:
This question appear incomplete because of the absence of options. However, metamorphic rocks are rocks that are formed from other pre-existing rocks under heat and pressure (both are usually high), causing them to twist and melt together. Metamorphism simply means a change in form of something and that's what happens here also.
Answer:
Given that
P = RT/V + a/V²
We know that
H= U + PV
For T= Constant (ΔU=0)
ΔH= ΔU +Δ( PV)
ΔH= Δ( PV)
P = RT/V + a/V²
P V= RT + a/V
dH/dV = d(RT + a/V)/dV
dH/dV = - a/V²
So the expression of dH/dV
b)
In isothermal process
(ΔU=0)
Now by putting the all values
ΔH = 17.06 L.atm
