Question

Two electric motors drive two elevators of equal mass in a three-story building 10 meters tall. Each elevator has a mass of 1,000 kg. The first elevator can do this work in 5.0 seconds. Calculate the power output of the first motor.
2.0 x 102 W
2.0 x 103 W
2.0 x 104 W
2.0 x 105 W

Answer 1

Answer:

The power output of the first motor is,  P = 2.0 x 10⁴ watts

Explanation:

Given data,

The height of the building, h = 10 m

The mass of the elevator, m = 1000 kg

The time duration of the motor to do this work, t = 5.0 s

The force acting on the elevator,

                                  F = m x g

                                    = 1000 x 9.8

                                     = 9800 N

The work done by the elevator,

                                W = F  x h

                                     = 9800 x 10

                                     = 98000 J

The power output of the first motor,

                                P = W / t

                                   = 98000 / 5

                                   = 19600 watts

                                   = 1.96 x 10⁴ watts

Hence, the power output of the first motor is, P = 2.0 x 10⁴ watts