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3 years ago

Can I have some help

Mathematics

1 answer:

JulijaS [17]3 years ago

7 0

Hey! This can look pretty confusing but, don’t worry I’m here to help! I actually just studied these.

So basically you’re wanting to solve for Y.
You can calculate this by cross multiplying and the answer to your question is 12.

I know how it is when you need help and you just can’t grasp something, so if you have absolutely anymore questions or concerns, post em in chat and I’ll be happy to try to answer.
Have a great evening and I hope this helped!
~Brooke❤️

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The table below shows a correct representation that 15 pounds (lb) of sugar cost $3:

SIZIF [17.4K]

Answer: True

Step-by-step explanation: There are 15 pounds and 3 dollars. 15 over 3 is $1 for 5 pounds.

4 0

3 years ago

Ok so this... is confusing the hell outta me any help? <br>

kap26 [50]

Answer:

y = 24

Step-by-step explanation:

The sum of the angles of a triangle is 180

A+B+C = 180

ABC = 60

We know 2x-4 = 60

2x -4+4 = 60+4

2x = 64

x = 64/2 = 32

A = 3x = 3(32) = 962x-4 = 60

B = 60

Using the first equation

96+ 60 +y = 180

156 +y =180

y = 180-156

y = 24

8 0

3 years ago

A public health organization reports that 40%of baby boys 6-8 months old in the United

Sveta_85 [38]

Using the binomial distribution, the probabilities are given as follows:

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.

0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.

Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

The values of the parameters for this problem are:

n = 10, p = 0.4.

The probability that more than 4 weigh more than 20 pounds is:

$P(X > 4) = 1 - P(X \leq 4)$

In which:

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.4)^{0}.(0.6)^{10} = 0.0061$

$P(X = 1) = C_{10,1}.(0.4)^{1}.(0.6)^{9} = 0.0403$

$P(X = 2) = C_{10,2}.(0.4)^{2}.(0.6)^{8} = 0.1209$

$P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.2150$

$P(X = 4) = C_{10,4}.(0.4)^{4}.(0.6)^{6} = 0.2502$

Hence:

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0061 + 0.0403 + 0.1209 + 0.2150 + 0.2502 = 0.6325$

$P(X > 4) = 1 - P(X \leq 4) = 1 - 0.6325 = 0.3675$

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.

The probability that fewer than 3 weigh more than 20 pounds is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0061 + 0.0403 + 0.1209 = 0.1673

0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.

For more than 7, the probability is:

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.4)^{8}.(0.6)^{2} = 0.0106$

$P(X = 9) = C_{10,9}.(0.4)^{9}.(0.6)^{1} = 0.0016$

$P(X = 10) = C_{10,10}.(0.4)^{10}.(0.6)^{0} = 0.0001$

Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

4 0

2 years ago

Can y’all help me I don’t get this

yarga [219]

Answer:

Its D

Step-by-step explanation: Since the answer choices B and C don't make sense, its between A and D.

A is actually wrong since it said that the lower class benefited protection from these lords and serfs. Also, the last two lines support D.

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3 years ago

Suppose you have $245. If you decide to spend it all on ice cream, you can buy 70 pints. If the price of a glass of lemonade is

guajiro [1.7K]

Answer:

198

Step-by-step explanation:

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3 years ago