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nignag [31]
3 years ago
14

Can I have some help

Mathematics
1 answer:
JulijaS [17]3 years ago
7 0
Hey! This can look pretty confusing but, don’t worry I’m here to help! I actually just studied these.

So basically you’re wanting to solve for Y.
You can calculate this by cross multiplying and the answer to your question is 12.

I know how it is when you need help and you just can’t grasp something, so if you have absolutely anymore questions or concerns, post em in chat and I’ll be happy to try to answer.
Have a great evening and I hope this helped!
~Brooke❤️
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Answer:

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Step-by-step explanation:

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6 0
3 years ago
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Given that cos θ = –12∕13 and θ is in quadrant III, find csc θ.
Trava [24]

Answer:

A

Step-by-step explanation:

We are given:

\displaystyle \cos(\theta)=-\frac{12}{13},\,\theta\in\text{QIII}

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So, the opposite side is 5, the adjacent side is 12, and the hypotenuse is 13.

And since θ is in QIII, sine/cosecant is negative, cosine/secant is negative, and tangent/cotangent is positive.

Cosecant is given by the hypotenuse over the opposite side. Thus:

\displaystyle \csc(\theta)=\frac{13}{5}

Since θ is in QIII, cosecant must be negative:

\displaystyle \csc(\theta)=-\frac{13}{5}

Our answer is A.

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2 years ago
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3 years ago
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