Answer:
0.42347247428
Step-by-step explanation:
my calcuator
7/16.52
For Problem #2, the second one should be 6x+4x+12, and the third one should be 10x+12
answer: the system had no solution
Answer:
x=6
Step-by-step explanation:
4(x + 4) + 2x= 52
We solve the bracket first by multiplying x+4 by 4
4x+16+2x=52
Collect like terms
4x+2x+16=52
6x+16=52
6x=52-16
6x=36
Divide both sides by 6
6x/6=36/6
x=36/6
x=6
To check for accuracy. We subsitute x for 6 in the equation and both sides of the equation must be equal
4(x + 4) + 2x= 52
4(6+4)+2(6)=62
4(10)+2(6)=52
40+12=52
52=52
1
Add the numbers
(
−
4
+
5
)
−
(
6
+
7
)
=
0
({\color{#c92786}{-4}}+{\color{#c92786}{5}})-(6+7)=xx^{0}
(−4+5)−(6+7)=xx0
(
1
)
−
(
6
+
7
)
=
0
({\color{#c92786}{1}})-(6+7)=xx^{0}
(1)−(6+7)=xx0
2
Add the numbers
1
−
(
6
+
7
)
=
0
1-({\color{#c92786}{6}}+{\color{#c92786}{7}})=xx^{0}
1−(6+7)=xx0
1
−
(
1
3
)
=
0
1-({\color{#c92786}{13}})=xx^{0}
1−(13)=xx0
3
Multiply the numbers
1
−
1
⋅
1
3
=
0
1{\color{#c92786}{-1}} \cdot {\color{#c92786}{13}}=xx^{0}
1−1⋅13=xx0
1
−
1
3
=
0
1{\color{#c92786}{-13}}=xx^{0}
1−13=xx0
4
Subtract the numbers
1
−
1
3
=
0
{\color{#c92786}{1-13}}=xx^{0}
1−13=xx0
−
1
2
=
0
{\color{#c92786}{-12}}=xx^{0}
−12=xx0
5
Combine exponents
−
1
2
=
0
-12={\color{#c92786}{xx^{0}}}
−12=xx0
−
1
2
=
1
-12={\color{#c92786}{x^{1}}}
−12=x1
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Solution
−
1
2
=
1
