We know, S = n/2 [ a + l ]
Here, a = 45
l = 108
Calculation of n:
a(n) = a + (n - 1)d
108 = 45 + (n - 1)1
108 - 45 = n - 1
63 + 1 = n
n = 64
Now, substitute in the expression:
S = 64/2 [ 45 + 108 ]
S = 32 [ 153 ]
S = 4896
In short, Your Answer would be 4896
Hope this helps!
10+45+16
The answer would be 71
Answer:
"A value that is substituted in for the variable in a function in order to generate an output value" is gonna be known as an input.
"A group of two numbers written in the form (x, y) where the x value represents a horizontal position and the y value represents a vertical position" is known as an ordered pair.
"A value generated by a function when an input value is substituted into the function and evaluated" is known as an output.
I hope I have helped with this problem. Have a good day.
You can first take out an x^2 from each number , 3x^6 - 39x^4 + 108x^2 = x^2 ( 3x^4 - 39x^2 + 108) Then just factor and solve for the zero's of the equation
Answer:

Step-by-step explanation:
Sum of m and one - third of n is :

Product of 3k to the sum is :
