Answer:
613 mg
Explanation:

Number of fargday's 
Here, I = 9.20 A
t = 10.5 min
= 10.5 x 60 seconds
So, 

= 0.0208 F
Here, 2e, 2F
2F = 1 mol of Ni

1 mol = 59 gm of Ni
0.0104 mol = 59 x0.0104 gm Ni
= 0.613 gm Ni
= (0.613 x 1000 ) mg of Ni
= 613 mg of Ni
Chemical would be the correct answer
What is the empirical formula for ribose (C5H10O5)?
C. CH20
Answer:
+3
Explanation:
-10 + 13 = +3
-10 IS THE NUMBER OF ELECTRONS
13 IS THE NUMBER OF PROTONS