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chubhunter [2.5K]
3 years ago
5

Two objects are dropped into beaker with layers of oil, rubbing alcohol, water and corn syrup. These objects are made of the sam

e substance, but object X is twice as large, so twice as heavy as object Z.
Which of these two objects will settle further down into the beaker, X, Z, both or neither?
(My teacher labeled this as a trick question)
Chemistry
1 answer:
Mademuasel [1]3 years ago
6 0
It all depends on the objects' densities ,because if they're less dense than the oil they will not even sink to the bottom of the beaker
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Snezhnost [94]

mass of pentane : = 30.303 g

moles of Al₂(CO₃)₃ : = 0.147

<h3>Further explanation</h3>

Given

1. Reaction

C₅H₁₂+8O₂→6H₂O+5CO₂.

45.3 g water

2. 2AlCl₃ + 3MgCO₃ → Al₂(CO₃)₃ + 3MgCl₂

37.2 MgCO₃

Required

mass of pentane

moles of Al₂(CO₃)₃

Solution

1. mol water = 45.3 : 18 g/mol = 2.52

From equation, mol ratio of C₅H₁₂ : H₂O = 1 : 6, so mol pentane :

= 1/6 x mol H₂O

= 1/6 x 2.52

= 0.42

Mass pentane :

= mol x MW

= 0.42 x 72.15 g/mol

= 30.303 g

2. mol MgCO₃ : 37.2 : 84,3139 g/mol = 0.44

mol Al₂(CO₃)₃ :

= 1/3 x mol MgCO₃

= 1/3 x 0.44

= 0.147

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