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2 years ago

What is the volume of 1.2 moles of oxygen gas (o2) at 295 k and 1.2 atm? 18 l 22 l 24 l 78 l

Chemistry

2 answers:

vaieri [72.5K]2 years ago

8 0

P x V = n x R x T

1.2 x V = 1.2 x 0.082 x 295

1.2 x V = 29.028

V = 29.028 / 1.2

V = 24 L

tigry1 [53]2 years ago

7 0

Answer:

The correct answer is the option: 24L

Explanation:

Hello!

Let's solve this!

To calculate this we use the gas equation:

P * V = n * R * T

We clear the volume:

V = (n * R * T) / P

V = (1.2mol * 0.082 (L * atm / K * mol) * 295K) /1.2atm

V = 24.19L

After calculations, we conclude that the correct answer is the option: 24L

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Do gold and silver have the same extensive properties

Pepsi [2]

Answer:

They do not

Explanation:

Gold is more advanced

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3 years ago

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2. Balance the equation below, and answer the following question: What volume of chlorine gas, measured at STP, is needed to com

Juliette [100K]

Balanced equation: 2Na(s) + Cl₂(g) ---> 2NaCl(s)

when we have STP conditions, we can use this conversion: 1 mol = 22.4 L

first, we have to convert grams to molecules using the molar mass, and then use mole to mole ratio from the balanced equation.

molar mass of Na= 23.0 g/mol
ratio: 2 mol Na= 1 mol Cl₂ (based on coefficients of balanced equation)

calculations:

$6.25 g Na ( \frac{1 mol Na}{23.0 g} ) ( \frac{1 mol Cl_2}{2 mol Na} ) ( \frac{22.4 L}{1 mol} )= 3.04 L$

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2 years ago

A hydrate is compound that included water molecules within its crystal structure. During an experiment to determine the percent

stellarik [79]

Answer:

The percent by mass of water in this crystal is:

<u>21.4%</u>

Explanation:

This exercise can be easily solved using a simple rule of three where the initial weight of the hydrated crystal (6,235 g) is taken into account as 100% of the mass, and the percentage to which the mass of 4.90 g corresponds (after getting warm). First, the values and unknown variable are established:

6,235 g = 100%
4.90 g = X

And the value of the variable X is found:

X = (4.90 g * 100%) / 6,235 g
X = approximately 78.6%.

The calculated value is not yet the percentage of the water, since the water after heating the glass has evaporated, therefore, the remaining percentage must be taken, which can be calculated by subtraction:

Water percentage = Total percentage - Percentage after heating.
<u>Water percentage = 100% - 78.6% = 21.4%</u>

4 0

3 years ago

Read 2 more answers

A 25.0-mL sample of 0.150 M hydrocyanic acid is titrated with a 0.150 M NaOH solution. The Ka of hydrocyanic acid is 4.9 × 10-10

lara [203]

Answer:

The pOH = 1.83

Explanation:

Step 1: Data given

volume of the sample = 25.0 mL

Molarity of hydrocyanic acid = 0.150 M

Molarity of NaOH = 0.150 M

Ka of hydrocyanic acid = 4.9 * 10^-10

Step 2: The balanced equation

HCN + NaOH → NaCN + H2O

Step 3: Calculate the number of moles hydrocyanic acid (HCN)

Moles HCN = molarity * volume

Moles HCN = 0.150 M * 0.0250 L

Moles HCN = 0.00375 moles

Step 3: Calculate moles NaOH

Moles NaOH = 0.150 M * 0.0305 L

Moles NaOH = 0.004575 moles

Step 4: Calculate the limiting reactant

0.00375 moles HCN will react with 0.004575 moles NaOH

HCN is the limiting reactant. It will completely be reacted. There will react 0.00375 moles NaOH. There will remain 0.004575 - 0.00375 = 0.000825 moles NaOH

Step 5: Calculate molarity of NaOH

Molarity NaOH = moles NaOH / volume

Molarity NaOH = 0.000825 moles / 0.0555 L

Molarity NaOH = 0.0149 M

Step 6: Calculate pOH

pOH = -log [OH-]

pOH = -log (0.0149)

pOH = 1.83

The pOH = 1.83

6 0

3 years ago

If 0.50 g of O2(g) reacts with excess H2(g), what is the volume of H2O(g) obtained from the reaction at STP?

ozzi

Answer:

0.7 L H2O

Explanation:

4 0

2 years ago