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densk [106]
2 years ago
14

How does the ionosphere affect radio frequencies?

Chemistry
1 answer:
Nesterboy [21]2 years ago
6 0
Due to the ability of ionized atmospheric gases to refract high frequency (HF, or shortwave) radio waves, the ionosphere can reflect radio waves directed into the sky back toward the Earth. Radio waves directed at an angle into the sky can return to Earth beyond the horizon.
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WHATS THE CORRECT ANSWER ANSWER ASAP
Jlenok [28]

Solar energy is a non-pollutant, which means it doesn't pollute the environment. so therefore A is the correct answer.

8 0
2 years ago
What is the pH of a solution with a concentration of 2.4 × 10-5 molar H3O+? Show, or explain, the work used to solve this proble
MrRissso [65]
pH=-log|H_{3}O^{+}|\\\\
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7 0
3 years ago
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In which state of matter do the particles spread apart and fill all the space available to them?
BlackZzzverrR [31]
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3 years ago
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If you start with 227.8 grams of iron and 128 grams of oxygen to produce iron oxide, what is the limiting reagent?
agasfer [191]

The balanced chemical equation between iron and oxygen to produce iron (III) oxide is,

4Fe(s) + 3O_{2}(g) ---> 2Fe_{2}O_{3}(s)

Mass of Fe = 227.8 g

Moles of Fe = 227.8 g Fe * \frac{1 mol Fe}{55.85 g Fe} = 4.079 mol Fe

Mass of oxygen = 128 g

Moles of O_{2} = 128 g O_{2}*\frac{1 mol O_{2}}{32 g O_{2}}= 4mol O_{2}

Calculating the limiting reactant: The reactant that produces the least amount of product will be the limiting reactant.

Mass of iron (III) oxide produced from Iron = 4.079 mol Fe * \frac{2 mol Fe_{2}O_{3}}{4 mol Fe}  *\frac{159.69 g Fe_{2}O_{3}}{1 mol Fe_{2}O_{3}} = 325.7 g Fe_{2}O_{3}

Mass of iron (III) oxide produced from oxygen=4 mol O_{2}*\frac{2 molFe_{2}O_{3}}{3 mol O_{2}}*\frac{159.69 g Fe_{2}O_{3}}{1 mol Fe_{2}O_{3}} =  425.84 g Fe_{2}O_{3}

Iron (Fe) produces the least amount of the product iron (III) oxide. So, Fe is the limiting reactant.

7 0
3 years ago
How many joules of energy are made by the loss of 100kg of mass using the formula E=mc2? please help!!!
asambeis [7]

Answer:

E = 3 × 10¹⁰ J

Explanation:

Mass, m = 100 kg

We need to find energy made by the loss of 100 kg of mass. The formula between the mass and energy is given by :

E = mc²

Where c is speed of light

Putting all the values, we get :

E = 100 kg × (3×10⁸ m/s)²

= 3 × 10¹⁰ J

So, the required energy is 3 × 10¹⁰ J.

6 0
3 years ago
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