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3 years ago

Find the value of t in the equation t + 5 + 3t = 1. A. –1 B. 1.5 C. 3 D. 6

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

3 0

The best method here is to plug in so plug in -1 (-1)+5+3(-1)=1 so the answer is A

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Fernando will divide 0.24 by 4 to help him solve a math problem. Which model below could represent this math problem

balandron [24]

Answer:

So the model should represent either $\frac{6}{100}$ or $\frac{3}{50}$ (its equivalent and simplified form.

Step-by-step explanation:

1) Originally the question wants to represent this quotient as tiles.

So, $\frac{\frac{24}{100}}{4} =\frac{24}{100} *\frac{1}{4} =\frac{6}{100}=$

We can still simplify it, but since we're dealing with 100 x 100 squares let's keep it this way

2) So the model should represent either $\frac{6}{100}$ or $\frac{3}{50}$ (its equivalent and simplified form.

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3 years ago

) The density of oil in a circular oil slick on the surface of the ocean at a distance of r meters from the center of the slick

Feliz [49]

Answer:

Therefore the mass of the of the oil is 409.59 kg.

Step-by-step explanation:

Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).

The area of the disk

=The area of the outer circle - The area of the inner circle

= $\pi (r+\triangle r)^2- \pi r^2$

$=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]$

$=\pi [2r\triangle r+(\triangle r)^2]$

Since (Δr)² is very small, So it is ignorable.

∴ $A=2\pi r\triangle r$

The density $\delta (r)= \frac{40}{1+r^2}$

We know,

Mass= Area× density

$=(2r \pi \triangle r)(\frac{40}{1+r^2}})$

Total mass $M=\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i$

Therefore

$\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i=\int_0^5 \frac{80r\pi }{1+r^2}dr$

$=40\pi[ln(1+r^2)]_0^5$

$=40\pi [ln(1+5^2)-ln(1+0^2)]$

$=40\pi ln(26)$

= 409.59 kg (approx)

Therefore the mass of the of the oil is 409.59 kg.

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3 years ago

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pochemuha

Answer:

=−368q2−23qr+544q+34r

Step-by-step explanation:

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3 years ago