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Sveta_85 [38]
4 years ago
7

In a physics laboratory experiment, a coil with 200 turns enclosing an area of 12cm2 is rotated in 0.040 s from a position where

its plane is perpendicular to the earth’s magnetic field to a position where its plane is parallel to the field. The earth’s magnetic field at the lab location is 6.0×10^−5T.
(a) What is the total magnetic flux through the coil before it is rotated? After it is rotated?
(b) What is the average emf induced in the coil?
Physics
1 answer:
Eddi Din [679]4 years ago
3 0

Answer

given,

turns in coil (n) = 200 turns

area (A)= 12 cm²

time(t) = 0.040 s

electric magnetic field = 6 × 10⁻⁵ T

θ = 0°

a) total magnetic flux

∅ = n B A cos θ

∅ = 200 x 6 × 10⁻⁵ x 0.0012 x cos 0°

∅ = 1.44 × 10⁻⁵  Wb

b) average emf induced

 E = \dfrac{d\phi }{dt}

 E = \dfrac{1.44 \times 10^{-6}}{0.040}

 E = 3.6 mV

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Answer:

D. The oxygen side is partially negative because electrons are pulled toward the oxygen side.

Explanation:

The water molecule is polar by the virtue of covalent bonds and the hydrogen bonds within and between its molecule.

The oxygen side is partially negative because the electrons are pulled toward the oxygen side.

Between oxygen and hydrogen that makes up the water molecule, oxygen is more electronegative.

An electronegative atom has more affinity for electrons. Since the electrons in the molecule of water is shared between hydrogen and oxygen, the more electronegative specie which is water draws the electron more to itself.

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8 0
3 years ago
Water having a density of 1000 kg/m^3 is flowing with a velocity of 3 m/s through a round pipe. There is a restriction within th
Fofino [41]

Answer:

12 m/s

Explanation:

Using the continuity equation, which is an extension of the conservation of mass law

ρ₁A₁v₁ = ρ₂A₂v₂

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ρ = density of the fluid flowing; note that the density of the fluid flowing (water) is constant all through the fluid's flow

A₁ = Cross sectional Area of the pipe at point 1 = (πD₁²/4)

A₂ = Cross sectional Area of the pipe at the restriction = (πD₂²/4)

v₁ = velocity of the fluid flowing at point 1 = 3 m/s

v₂ = velocity of the fluid flowing at The restriction = ?

ρ₁A₁v₁ = ρ₂A₂v₂

Becomes

A₁v₁ = A₂v₂ (since ρ₁ = ρ₂)

(πD₁²/4) × 3 = (πD₂²/4) × v₂

3D₁² = D₂² × v₂

But

D₂ = (D₁/2)

And D₂² = (D₁²/4)

3D₁² = D₂² × v₂

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(D₁²/4) × v₂ = 3D₁²

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A charged particle decelerates as it moves from location a to location b. if va = 160 v and vb = 100 v, what is the sign of the
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The sign of the charged particle is positively charged.

<h3>What is potential difference?</h3>
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  • Voltage is the possibility of a single charge flowing. The need to flow increases with voltage.
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The potential difference between the 2 points determines the movement of that particle. An electron moves from lower to higher potential which is negatively charged, and a positively charged particle moves  from higher to lower potential.

Now, since the particle is moving from a point A having 160 v potential to point B having 100 v potential that is it is moving from higher potential to a lower potential therefore the particle will be a positively charged one.

Learn more about potential difference,

brainly.com/question/23716417

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3 0
1 year ago
You have to push a heavy box across three surfaces: a grassy field , ice rink, and a concrete playground. Which surface will be
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Explanation:

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How fast would a 20 kg dog have to run, to reach a momentum of 120 kg x m/s? Include unit in your answer. Worth 40 points!
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Answer:

6 m/s

Explanation:

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3 years ago
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