A charged particle decelerates as it moves from location a to location b. if va = 160 v and vb = 100 v, what is the sign of the

Question

Aliun [14]

1 year ago

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A charged particle decelerates as it moves from location a to location b. if va = 160 v and vb = 100 v, what is the sign of the

charged particle?

Physics

1 answer:

skelet666 [1.2K] · Answer 1 · 2024-02-29T21:35:20+03:00

The sign of the charged particle is positively charged.

<h3>What is potential difference?</h3>

When a single charge is transported in an electric field, work is done by the potential difference (also known as electrical potential).
There is potential energy stored in this charge that could flow when work is done on it.
Voltage is the possibility of a single charge flowing. The need to flow increases with voltage.
Here, voltage can be the potential differences.

The potential difference between the 2 points determines the movement of that particle. An electron moves from lower to higher potential which is negatively charged, and a positively charged particle moves from higher to lower potential.

Now, since the particle is moving from a point A having 160 v potential to point B having 100 v potential that is it is moving from higher potential to a lower potential therefore the particle will be a positively charged one.

Learn more about potential difference,

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