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Aliun [14]
3 years ago
11

How do I fix my task bar thing

Physics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

go to settings and find what your looking for

Explanation:

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PLEASE HELP ASAP! i will really appreciate it
Setler79 [48]
What you’re doing is so easy pay attention more I think
4 0
3 years ago
A 120 V electric heater draws a current of 14.1 A. What is the resistance, in ohms?
Sav [38]

Answer:

8.5 ohms

Explanation:

from ohms law

V=IR

120=14.1R

divide both sides by 14.1

120/14.1=14.1R/14.1

R=8.5ohms

5 0
3 years ago
Read 2 more answers
10. Find the mass density of a ball with 22.0 g and a radius of 0.875 cm.
Ede4ka [16]

Answer:

Mass (m) = 22.0 g

Radius (r) = 0.875 cm

Density (d) = ?

First find ( volume) ;

v =  \frac{4}{3} \pi \:  {r}^{3}  \\  \\ v =  \frac{4}{3}  \times 3.14 \times ( {0.875)}^{3}  \\  \\ v =  \frac{4}{3}   \times 3.14 \times 0.66992187  \:  {cm}^{3} \\  \\ v = 2.8 \:  {cm}^{3}

Density =  \frac{mass}{volume}  \\  \\ d =  \frac{m}{v}  \\  \\ d =  \frac{22}{2.8}  \\  \\ d = 7.857 \:  \frac{g}{ {cm}^{3} }

I hope I helped you^_^

7 0
3 years ago
A potential difference of 3.27 nV is set up across a 2.16 cm length of copper wire that has a radius of 2.33 mm. How much charge
miskamm [114]

Answer:

Charge = 4.9096 x 10⁻⁷ C

Explanation:

First, we find the resistance of the copper wire.

R = ρL/A

where,

R = resistance = ?

ρ = resistivity of copper = 1.69 x 10⁻⁸ Ω.m

L = Length of wire = 2.16 cm = 0.0216 m

A = Cross-sectional area of wire = πr² = π(0.00233 m)² = 1.7 x 10⁻⁵ m²

Therefore,

R = (1.69 x 10⁻⁸ Ω.m)(0.0216 m)/(1.7 x 10⁻⁵ m²)

R = 2.14 x 10⁻⁵ Ω

Now, we find the current from Ohm's Law:

V =IR

I = V/R

I = 3.27 x 10⁻⁹ V/2.14 x 10⁻⁵ Ω

I = 1.52 x 10⁻⁴ A

Now, for the charge:

I = Charge/Time

Charge = (I)(Time)

Charge = (1.52 x 10⁻⁴ A)(3.23 x 10⁻³ s)

<u>Charge = 4.9096 x 10⁻⁷ C</u>

8 0
4 years ago
Your electric drill rotates initially at 5.35 rad/s. You slide the speed control and cause the drill to undergo constant angular
Agata [3.3K]

Answer:

The  angular displacement  is  \theta  =  29.6 \ rad

Explanation:

From the question we are told that

     The initial angular speed is  w =  5.35 \ rad/s

      The angular acceleration is  \alpha  =  0.331 rad /s^2

      The time take is  t =  4.81 \ s

     

Generally the angular displacement is mathematically represented as

          \theta  =  w * t  + \frac{1}{2} \alpha  * t^2

substituting values

         \theta  =  5.35 * 4.81  + \frac{1}{2}  *  0.331  * (4.81)^2

         \theta  =  29.6 \ rad

3 0
3 years ago
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