The famous Newton’s Third Law states that “For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object.”
By using this,
10grams or 0.01kg of bullet with speed 400 m/sec and 5kg gun recoil with speed suppose ‘v’.
0.01×400=5×v
4/5=v
v=0.8m/sec ANSWER.
Answer:
1470 W
Explanation:
Power: This can be defined as the rate at which work is done or energy is used up. The S.I unit of power is Watt (W).
The expression for power is given as,
P = Energy/time
P = mgh/t ...................... Equation 1
Where P = power, m = mass, h = height, t = time, g = acceleration due to gravity.
Given: m = 75 kg, g =9.8 m/s², h = 1 m, t = 1 s.
Substitute into equation 1
P = (75×1×9.8)/1
P = 735 W.
From the above,
1 hp = 735 W
2 hp = (2×735) W
2 hp = 1470 W.
Hence 2 hp = 1470 W
The maximum torque she can apply to the spark plug is 12.76 Nm.
<h3>
What is torque?</h3>
Torque is the rotational equivalent of linear force obtained by taking the product of force and the radius of the applied force.
τ = Fr
where;
- F is the applied force
- r is the radius
The maximum torque she can apply to the spark plug is calculated as follows;
τ = 58 x (0.22)
τ = 12.76 Nm
Thus, the maximum torque she can apply to the spark plug is 12.76 Nm.
Learn more about torque here: brainly.com/question/14839816
